The first thing you should know to solve this problem is the conversion of pounds to kilograms:
1lb = 0.45 Kg
We can solve this problem by a simple rule of three
1lb ---> 0.45Kg
125lb ---> x
Clearing x we have:
x = ((125) / (1)) * (0.45) = 56.25 Kg.
Answer
her mass expressed in kilograms is 56.25 Kg.
Answer:
The final velocity of the thrower is
and the final velocity of the catcher is
.
Explanation:
Given:
The mass of the thrower,
.
The mass of the catcher,
.
The mass of the ball,
.
Initial velocity of the thrower, ![v_{it} = 3.90~m/s](https://tex.z-dn.net/?f=v_%7Bit%7D%20%3D%203.90~m%2Fs)
Final velocity of the ball, ![v_{fb} = 33.5~m/s](https://tex.z-dn.net/?f=v_%7Bfb%7D%20%3D%2033.5~m%2Fs)
Initial velocity of the catcher, ![v_{ic} = 0~m/s](https://tex.z-dn.net/?f=v_%7Bic%7D%20%3D%200~m%2Fs)
Consider that the final velocity of the thrower is
. From the conservation of momentum,
![&& m_{t}v_{ft} + m_{b}v_{fb} = (m_{t} + m_{b})v_{it}\\&or,& v_{ft} = \dfrac{(m_{t} + m_{b})v_{it} - m_{b}v_{fb}}{m_{t}}\\&or,& v_{ft} = \dfrac{(70 + 0.0480)(3.90) - (0.0480)(33.5)}{70}\\&or,& v_{ft} = 3.88~m/s](https://tex.z-dn.net/?f=%26%26%20m_%7Bt%7Dv_%7Bft%7D%20%2B%20m_%7Bb%7Dv_%7Bfb%7D%20%3D%20%28m_%7Bt%7D%20%2B%20m_%7Bb%7D%29v_%7Bit%7D%5C%5C%26or%2C%26%20v_%7Bft%7D%20%3D%20%5Cdfrac%7B%28m_%7Bt%7D%20%2B%20m_%7Bb%7D%29v_%7Bit%7D%20-%20m_%7Bb%7Dv_%7Bfb%7D%7D%7Bm_%7Bt%7D%7D%5C%5C%26or%2C%26%20v_%7Bft%7D%20%3D%20%5Cdfrac%7B%2870%20%2B%200.0480%29%283.90%29%20-%20%280.0480%29%2833.5%29%7D%7B70%7D%5C%5C%26or%2C%26%20v_%7Bft%7D%20%3D%203.88~m%2Fs)
Consider that the final velocity of the catcher is
. From the conservation of momentum,
![&& (m_{c} + m_{b})v_{fc} = m_{b}v_{it}\\&or,& v_{fc} = \dfrac{m_{b}v_{it}}{(m_{c} + m_{b})}\\&or,& v_{fc} = \dfrac{(0.048)(33.5)}{(55.0 + 0.0480)}\\&or,& v_{fc} = 0.029~m/s](https://tex.z-dn.net/?f=%26%26%20%28m_%7Bc%7D%20%2B%20m_%7Bb%7D%29v_%7Bfc%7D%20%3D%20m_%7Bb%7Dv_%7Bit%7D%5C%5C%26or%2C%26%20v_%7Bfc%7D%20%3D%20%5Cdfrac%7Bm_%7Bb%7Dv_%7Bit%7D%7D%7B%28m_%7Bc%7D%20%2B%20m_%7Bb%7D%29%7D%5C%5C%26or%2C%26%20v_%7Bfc%7D%20%3D%20%5Cdfrac%7B%280.048%29%2833.5%29%7D%7B%2855.0%20%2B%200.0480%29%7D%5C%5C%26or%2C%26%20v_%7Bfc%7D%20%3D%200.029~m%2Fs)
Thus, the final velocity of thrower is
and that for the catcher is
.
Answer:
transmission: the passing of a wave through an object
Explanation:
Answer:
a) When moving towards a high pressure center the pressure values increase in the equipment
b) This area is called high prison since the weight of the atmosphere on top is maximum
Explanation:
A) A high atmospheric pressure system is an area where the pressure is increasing the maximum value is close to 107 Kpa, the other side as low pressure can have small values 85.5 kPa.
When moving towards a high pressure center the pressure values increase in the equipment
B) This area is called high prison since the weight of the atmosphere on top is maximum
in general they are areas of good weather
Answer:
Explanation:
Exercise controls weight. Exercise can help prevent excess weight gain or help maintain weight loss. ...
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Exercise improves mood. ...
Exercise boosts energy. ...
Exercise promotes better sleep. ...
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Exercise can be fun … and social!