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Vinil7 [7]
4 years ago
5

An ice cube can slide around the inside of a vertical circular hoop of radius . It undergoes small-amplitude oscillations if dis

placed slightly from the equilibrium position at the lowest point.Find an expression for the period of these small-amplitude oscillations.Give your answer in terms of R and constants g and pi.
Physics
1 answer:
klasskru [66]4 years ago
4 0

Answer:

T=2\pi \times \sqrt {\frac {g}{\mu R}

Explanation:

\mu mw^{2}R=mg

where m is the mass, g is acceleration due to gravity

The masses m are on both sides hence they cancel

W=\sqrt {\frac {g}{\mu R}

We know that T=2\pi W and substituting W with the above equation then

T=2\pi \times \sqrt {\frac {g}{\mu R}

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Answer:

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