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ale4655 [162]
4 years ago
9

You invested $9000 in 2 funds paying 4% and 7% annual interest. At the end of the year, the total interest from these investment

s was $555. How much was invested at each rate?
Mathematics
1 answer:
Art [367]4 years ago
8 0

Answer: he invested $2500 in fund 1 and $6500 in fund 2

Step-by-step explanation:

Let x represent the amount of money invested in fund 1.

Let y represent the amount of money invested in fund .

Total amount of money invested in fund 1 and fund 2 is

x + y = 9000

x = 9000 - y - - - - - - - - - 1

The formula for simple interest is expressed as

I = PRT/100

Where

P is the principal or initial amount.

T is the duration in years

R is the number rate.

For fund 1,

R = 4%

T = 1 year

P = x

I = (x × 4 × 1)/100 = 0.04x

For fund 2,

R = 7%

T = 1 year

P = y

I = (y × 7 × 1)/100 = 0.07y

At the end of the year, the total interest from these investments was $555. This means that

0.04x + 0.07y = 555 - - - - - - - -2

Substituting equation 1 into equation 2, it becomes,

0.04( 9000 - y) + 0.07y = 555

360 - 0.04y + 0.07y = 555

- 0.04y + 0.07y = 610 - 360

0.03y = 195

y = 195/0.03 = 6500

x = 9000 - 6500

x = $2500

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