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melomori [17]
3 years ago
7

The length of a rectangle is 4x and the width of the rectangle is x^2 - 2x + 6. What is the area of the

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Step-by-step explanation:

Area of rectangle(A)=l×b

=4x×(x^2-2x+6)

= 4x^3-8x^2+24x

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You flip a coin 3 times. What is the probability that it comes up heads all three times (HHH)?
Volgvan

Answer:

1 out of 8

Step-by-step explanation:

If you flip a coin there are eight possible outcomes:

HHH

HHT

HTT

TTT

THH

TTH

THT

HTH

SO the probability of getting all heads is 1 over 8.

Hope this helps

5 0
3 years ago
Use the Integral Test to determine whether the series is convergent or divergent
Inga [223]

Answer:

A. \sum_{n=1}^{\infty}\frac{n}{e^{15n}} converges by integral test

Step-by-step explanation:

A. At first we need to verify that the function which the series is related (\frac{n}{e^{15n}}) fills the necessary conditions to ensure that the test is effective.

*f(x) must be continuous or differentiable

*f(x) must be positive and decreasing

Let´s verify that f(x)=\frac{n}{e^{15n}} fills these conditions:

*Considering that eˣ≠0 for all x, the function f(x)=\frac{n}{e^{15n}} does not have any discontinuities, so it´s continuous

*Because eˣ is increasing:

      if a<b ,then eᵃ<eᵇ

      if 0<eᵃ<eᵇ ,then 1/eᵃ > 1/eᵇ

      if 1/eᵃ > 1/eᵇ and a<b, then a/eᵃ<b/eᵇ

  We conclude that f(x)=\frac{n}{e^{15n}} is decreasing

*Because eˣ is always positive and the sum is going from 1 to ∞, this show that f(x)=\frac{n}{e^{15n}} is positive in [1,∞).

Now we are able to use the integral test in f(x)=\frac{n}{e^{15n}} as follows:

\sum_{n=1}^{\infty}\frac{n}{e^{15n}}\ converges\ \leftrightarrow\ \int_{1}^{\infty}\frac{x}{e^{15x}}\ dx\ converges

Let´s proceed to integrate f(x) using integration by parts

\int_{1}^{\infty}\frac{x}{e^{15x}}\ dx=\int_{1}^{\infty}xe^{-15x}\ dx

Choose your U and dV like this:

U=x\ \rightarrow dU=1\\ dV=e^{-15x}\ \rightarrow V=\frac{-e^{-15x}}{15}

And continue using the formula for integration by parts:

\int_{1}^{\infty}Udv = UV|_{1}^{\infty} - \int_{1}^{\infty}Vdu

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{-1}{15} \int_{1}^{\infty}e^{-15x}\ dx

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{-1}{15}(\frac{-1}{15e^{15x}})|_{1}^{\infty}

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{-x}{15e^{15x}}|_{1}^{\infty} -\frac{1}{225e^{15x}}|_{1}^{\infty}

Because we are dealing with ∞, we´d rewrite it as a limit that will help us at the end of the integral:

\int_{1}^{\infty}xe^{-15x}\ dx= \lim_{b \to{\infty}}(\frac{-x}{15e^{15x}}|_{1}^{b}-\frac{1}{225e^{15x}}|_{1}^{b})

\int_{1}^{\infty}xe^{-15x}\ dx= \lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}}-(\frac{-1}{15e^{15}}-\frac{1}{225e^{15}})

\int_{1}^{\infty}xe^{-15x}\ dx= ( \lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}})+\frac{1}{15e^{15}}(1-\frac{1}{15})

We only have left to solve the limits, but because b goes to  ∞ and it is in an exponential function on the denominator everything goes to 0

\lim_{b \to{\infty}} \frac{-b}{15e^{15b}}-\frac{1}{225e^{15b}} = 0

\int_{1}^{\infty}xe^{-15x}\ dx= \frac{1}{15e^{15}}(1-\frac{1}{15})

Showing that the integral converges, it´s the same as showing that the series converges.

By the integral test \sum_{n=1}^{\infty}\frac{n}{e^{15n}} converges

7 0
3 years ago
1. A map has a scale 3 cm: 4 miles. What is the actual distance between two cities that are
Vera_Pavlovna [14]

The actual distance between the two cities are 30 miles.

<h3>What is a scale drawing?</h3>

A scale drawing is a smaller diagram of a larger image / building / object. The scale drawing is usually reduced at a constant dimension

<h3>What is the actual distance between the two cities?</h3>

The actual distance between the two cities = (22.5 X 4) / 3 = 30 miles

To learn more about scale drawings, please check: brainly.com/question/147532

6 0
2 years ago
Please help me with this question! Thank you :)
madreJ [45]

Answer:

y=x-3

Step-by-step explanation:

Graph y=x-5 and the point (1,-2). You want your slope to be the same for the lines to be parallel. The slope in the given equation is 1/1. Type into a graphing calculator y=x- and pick a number greater than negative five since the point (1,-2) is above the given line. Guess and checking reveals -3 to be the correct answer. Therefore, your answer is y=x-3.

5 0
3 years ago
Which represents the solution(s) of the equation x2 = 289?
sergeinik [125]

Answer:

B) x = +/- 17

Step-by-step explanation:

3 0
3 years ago
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