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Tems11 [23]
3 years ago
15

Jeremi is interested in healthy living, fitness and nutrition. He wants to make sure sugar makes up less than 10% of his food ea

ch day. About half of jeremi's food ir protein and healthy fats, two thirds of the remainder is complex carbohydrates like veggies and whole grains, and the rest of his food is sugary treats. What percent of Jeremi's current diet is sugary treats?
Mathematics
2 answers:
allochka39001 [22]3 years ago
7 0
<span>We are given that 1/2 of Jeremi's diet is protein and healthy fats, so we can eliminate that half and focus on the remaining portion. The remaining half can be written as 3/6, which aids in removing the 2/3 diet that are complex carbohydrates - we simply remove two of the 3 sixths, leaving 1/6 of Jeremi's diet as sugary treats. 1/6 is equal to 16.666...%.</span>
Yuri [45]3 years ago
5 0
This is the concept of arithmetic:
fraction of:
Protein+healthy fats=1/2
carbohydrates=2/3×1/2=1/3
sugary treats=1-(1/3+1/2)= 1/6
thus the percentage of sugary treats in the current diet will be:
(fraction of sugary treats)×(percentage of the diet)
=1/6×10
=10/6
=1 2/3 %
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Last question please
MatroZZZ [7]

Let's try an make a formula to make things easy.

_________________________________________________

Look at Andrew's pattern, it goes up 6 every time. Lets look at the 6 times table

6 times table:           6, 12, 18, 24, ...

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First think, how would you work out the <u>7</u>th term in the <u>6</u>th times table?

You would do <u>6</u> times <u>7</u>.

So the formula for the 6th times table is:

6n     (where n is the term you want to find out)

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So to get the 9th term in the 6 times table, you would replace the n with 9, like so:

9th term in 6 times table = 6 x 9 = 54

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Now lets compare the 6 times table to Andrew's pattern:

6 times table:           6, 12, 18, 24,

Andrew's pattern:     3, 9, 15, 21,

_____________________________________

If you look, you can see that Andrew's pattern is the 6 times table minus 3!

So what would be the formula for Andrew pattern?

---> it would be:  6n - 3   (since it's the 6 times table but minus 3)

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We can use this formula to easily work out the 20th term in Andrew's pattern!:

20th term = 6 x 20 - 3 = 120 - 3 = <u>117</u>    (remember, replace the n with 20)

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Now let's make a formula for Ben's pattern!

Ben's pattern goes up in 5s, so lets compare it to the 5 times table:

5 times table:       5, 10, 15, 20

Ben's pattern:       3, 8, 13, 18,

The formula for the 5 times table is 5n, and Ben's pattern is the 5 times table but minus 2.

So the formula for Ben's pattern is: 5n - 2

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<u>Now swap out the n for 20</u>  (to get the 20th term):

20th term = 5 x 20 - 2 = 100 - 2 = <u>98</u>

_________________________________________

So Andrew's 20th term is <u>117</u>, and Ben's 20th term is <u>98</u>.

All we do now is subtract them to find the difference:

117 - 98 = <u>19</u>

- - - - - - - - - - - - - - - - - - - - - - - - -

Answer:

Ben's 20th term is smaller by 19!

- - - - - - - - - - - - - - - - - - - - - - - - - -

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KengaRu [80]

Answer:

<h2>0i</h2>

Step-by-step explanation:

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