Whats the slope of a line if its plotted (0,0) and (3,6), find the y-intercept of the line. Write an equation for the line using
your answers. Find one more point that lies on the line. Explain why that point is also a solution to the function. (Please explain your answers so I could understand it more) thanks guys!
To find the slope you do the method Y2-Y1 -------- X2-X1 So you do 6-0=6 and 3-0=3. That would be 6/3 and then, you simplify it. Your slope is 2. To find the y-intercept you have to do the point slope form, then, you do the slope intercept form Y-Y1=m(x-x1) You do y-6=2(x-3) Y-6=2x+(-6) You add six to both sides The equation is y=2x The y-intercept is -6 One more point on the line would be (4,8). Because if you look at the slope it is 2/1. When plotting a point you look at the slope as rise over run. The two is the rise and the 1 is the run. So you go to (3,6) and add 1 to the 3. Then, you add 2 to the 6 to get (4,8). That's why that point is a solution to the function. You could also do (2,4) if you did the opposite and subtracted the 2 and 1 to make the bottom half of the line.
so slope=rise/run so if we plot the points and find how high and how long it went we see that the slope=6/3=2 slope=2
since the line goes through the origin (0,0) the y-intercept=(0,0) and the equation is y=mx+b m=slope b=how much away from the origin whic is not applicable in this problem. so y=2x
