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sweet-ann [11.9K]
3 years ago
6

$210 bicycles; 25% discount

Mathematics
1 answer:
cricket20 [7]3 years ago
3 0

Answer: $157.50 is the sale price

Step-by-step explanation:

because there is a 25% discount, 75% of the regular price will be the sale price

75% x 210 = $157.50 is the sale price

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Paul uses the function y = 7x + 30 to model the situation. What score does Paul’s model predict for 3 hours of homework?
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7 he gets 7 becuse he only did 7#43/6/h

Step-by-step explanation:

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3 years ago
Two perpendicular lines intersect at the origin. If the slope of the first line is -1/2, what is the equation of the second line
Dovator [93]

bearing in mind that perpendicular lines have <u>negative reciprocal</u> slopes.

now, they both intersect at 0,0, namely they both pass through it, we know the slope of the first one, so

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{1}}\qquad \stackrel{negative~reciprocal}{+\cfrac{2}{1}\implies 2}}

so, we're really looking for the equation of a line whose slope is 2, and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=2(x-0)\implies y=2x

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3 years ago
Solve e / e = mc2 and m =3 and c = 3
faust18 [17]
\text{e = mc}^2

\text{Given that m = 3 and c = 3,}

e = (3)(3)^2 = 27

Answer: e = 27
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3 years ago
The following question has two parts. First, answer part A. Then, answer part B.
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Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

8 0
3 years ago
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