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suter [353]
3 years ago
13

PLEASE, PLEASE, PLEASE HELP ME!!!! I NEED THE ANSWER IN ONE HOUR!!! Ben has 57 toys. 15 of them are new, 9 are his favorite ones

; 2 are new and favorite. Ben is going to give away all of his toys that are neither new nor favorite. How many toys will he give away?
Mathematics
1 answer:
storchak [24]3 years ago
3 0
So.... there are a total of 57 toys, which the new and favorites ones are not going to be sold.

The equation would ultimately go into 57 - (15+9+2), which would equal to 31. Ultimately, he sells 31 toys and have 26 left over.

in short, subtracting 57 with the sum of 15+9+2 would equal to 31 toys which means that he sells the 31 toys.
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P is a prime number and q is a positive integers such that p + q = 1696 IF P and Q are co primes and their Lcm is 21879 Then fin
Stolb23 [73]

Answer:

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Q = 1 6 8 3

Step-by-step explanation:

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4 0
2 years ago
I NEED HELP ASAP PLEASE<br><br> What is the quotient <br> x + 5 / 4x^2 + 25x + 12
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Answer:

4x+5-13/(x+5)

Step-by-step explanation:

The solution is attached to my answer.

8 0
3 years ago
Mr. Akika has 30 24-cent and 33-cent stamps all told. The stamps are worth $8.91. How many of each kind of stamp does he have?
riadik2000 [5.3K]

Answer:

  • 24-cent: 11
  • 33-cent: 19

Step-by-step explanation:

I find it easiest to solve these using the variable to represent the number of the most-expensive item. Let x represent the number of 33-cent stamps. Then the total value (in cents) is ...

  33x +24(30 -x) = 891

  9x = 171 . . . . . . . . . . . . . subtract 24(30), collect terms

  x = 19 . . . . . . . . . . . . divide by 9

  30-x = 11 . . . . . . . find the number of 24-cent stamps

Mr. Akika had 11 24-cent stamps and 19 33-cent stamps.

_____

<em>Additional comment</em>

You seem to have several of these to solve. They all have a similar solution.

If we let x represent the number of higher-value items, N, the total number of items, V the total value, and v1 and v2 the individual values (v2 > v1), the equation is ...

  v2(x) +v1(N -x) = V

  x(v2 -v1) = V -v1·N

  x = (V -v1·N)/(v2 -v1) . . . . generic solution

Using this formula in the problem here, we find ...

  x = (891 -24(30))/(33 -24) = 171/9 = 19 . . . as above

7 0
2 years ago
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UNO [17]
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4/80x + 5/80x = 1
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8 0
3 years ago
What is the reason for statement 4 in this proof?
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As we all know: A=A, B=B, mx=mx, nothing changes.

So the answer is D
5 0
3 years ago
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