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blondinia [14]
3 years ago
6

Look at the following expression. Are there any values of x for which the expression is not defined under the set of real number

s? Explain your reasoning. (2 points)
\frac{4}\sqrt{x+2}
Mathematics
1 answer:
almond37 [142]3 years ago
4 0

The expression \frac{4}{\sqrt{x+2} } is not defined at x= -2 & for all values of x  less than -2 .

<u>Step-by-step explanation:</u>

We have , a given expression as \frac{4}{\sqrt{x+2} } : Basically we need to find domain for this function and see for which values of x the above function is undefined . Domain of a function is the set of values of x for which the function is defined . We have a rational expression, \frac{4}{\sqrt{x+2} }  it's a fractional function which means denominator can be 0 . Denominator = \sqrt{x+2} \neq 0

⇒ \sqrt{x+2} \neq 0

⇒ x+2\neq 0

⇒ x \neq  -2

So , x \neq  -2 . Also , Denominator is a square root expression so it can't be negative inside root ∴ x+2 > 0 ⇒ x> -2 i.e. x must be greater than -2.

Therefore, the expression \frac{4}{\sqrt{x+2} } is not defined at x= -2 & for all values of x  less than -2 .

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