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alekssr [168]
3 years ago
14

HELP PLS

Mathematics
1 answer:
OLga [1]3 years ago
8 0

Answer:

D hope this helps

Step-by-step explanation:

-y •2=-2

-2+2=0

4x+x=5x

6+3=9

5x=9

9 divided by 5

x=1.9

So there for I think the answer is 2 it’s closest to 1.9

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Suppose each cube in this figure is a -inch cube. Select all that are true.
nevsk [136]

Answer:

I think C

Step-by-step explanation:

8 0
3 years ago
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The perimeter of a square is 64 cm.<br> What is the length of the diagonal of the square?
Angelina_Jolie [31]
the diagonal length and probably be 22.2
7 0
3 years ago
Jose wants to build a rectangular kennel for his dog. His dad will let him use a spot in the corner of the yard that is 12 feet
Butoxors [25]
Hello!

We don't need to find the exact perimeter of the fencing, just an estimate.

We will round 12 ft 3 in to 12 ft, because it is closer to 12 ft than 13 ft.

We will also round 8 ft 11 in to 9 ft because there are 12 inches in a foot, which makes 9 ft closer.

The formula for perimeter of a rectangle is:

P = 2l × 2w

The length is about 12 feet and the width is about 9 feet.

Substitute the length and width:

P = 2(12) + 2(9)

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P = 24 + 18

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Jose will need about 42 feet of fencing.
8 0
3 years ago
Please help me asap​
Leto [7]
1. D 12 2/7
2. 22 7/9 which is B hope this helps
7 0
3 years ago
A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
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