Factor completely. 5x2 - 45 5(x + 3)(x - 3) 5(x2 - 45) 5(x - 9)(x + 9) (5x + 9)(x - 5)

Mathematics

2 answers:

stellarik [79]3 years ago

4 0

$5x^2 - 45 = 5(x^2 - 9) = 5(x^2 - 3^2) = 5(x - 3) (x + 3)$

Answer: 5(x - 3) (x + 3)

Leona [35]3 years ago

4 0

Answer:

Option A is correct

$5(x+3)(x-3)$

Step-by-step explanation:

Using identity rule:

$(x^2-a^2) = (x-a)(x+a)$

To factor completely:

$5x^2-45$

Take 5 common out we have;

$5(x^2-9)$

Apply the identity rule

then;

$5(x+3)(x-3)$

Therefore, the complete factored of the given equation is: $5(x+3)(x-3)$

You might be interested in

What is the f(n) runtime of the following pseudocode: sum = 0 for A = N/2 downto 1 for B = 1 to 4N increment sum by B

nikitadnepr [17]

Answer:

f(N) = 2+ N/2 + 6N² units of time.

Step-by-step explanation:

Assigning 0 to the variable sum takes one unit of time.

Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have

f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).

5 0

3 years ago

Show your solution follow the steps<br>need an answer, please need an answer, please.

Alex777 [14]

Answer:

after calculating I got this answer.

hope this answer helps you dear...take care