When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula
for
0=ax²+bx+c
![x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%2B%2F-%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
so for
0=-16t²+25t+3
a=-16
b=25
c=3
so
![x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-25%2B%2F-%5Csqrt%7B25%5E2-4%28-16%29%283%29%7D%7D%7B2%28-16%29%7D)
![x=\frac{-25+/-\frac{625+192}}{-32}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-25%2B%2F-%5Cfrac%7B625%2B192%7D%7D%7B-32%7D)
![x=\frac{-25+/-\frac{817}}{-32}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-25%2B%2F-%5Cfrac%7B817%7D%7D%7B-32%7D)
it has to be a positive time
so it will hit the ground after
![\frac{25+\sqrt{817}}{32}](https://tex.z-dn.net/?f=%5Cfrac%7B25%2B%5Csqrt%7B817%7D%7D%7B32%7D)
seconds
7 is infinite 6 is 4/3 5 is zero 4 is negative 5/4
It would be 6n because 2times 3 is 6 and bring down the n
Answer:
Step-by-step explanation:
B. Yes, because it passes the vertical line test, is the answer.
48 feet
Divide 858 by 18 to get 47.6 > simplify > 48 feet