Your five number also know as the box plot values would be
min-11
q1-14
median-16
q3-20
max-24
So your median would be 16
Answer:
x>-1
Step-by-step explanation:
solve this normally like a linear equation
3x + 1 >x-1
collect like terms
3x-x>-1-1
2x>-2
x>-2/2
x>-1
First do ,60 divided by 7 =_____. Then do The product of that equation divided by 8. Then ur answer to that equation is a factor for the last equation u have to do witch is The product of ______ divided by 8, Then multiple that product by 3 like this (3❌_______=_______) then u have ur answer. Hope u understand more now that I've helped
The true question should be like this:
<span>What is the center and radius of the following circle: x^2 + (y _ 6)^2 = 50,
circle quation formula is (x-a)^2 + (y-b)^2 = R², so by identifying each term, we find </span>(x-a)^2=x^2 = (x-0)^2, (y-b)^2= (y _ 6)^2, R² = 50, implies R =5sqrt(2),
it is easy to identify that the center is (a,b)= (0, 6)
the radius is R =5sqrt(2),