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Gekata [30.6K]
3 years ago
13

Which of the following shows the union of the sets? {1, 4, 8, 12} {2, 4, 6, 8}

Mathematics
2 answers:
Sonbull [250]3 years ago
8 0

Answer:

{1, 2, 4, 6, 8, 12}

Step-by-step explanation:

Union of the sets is the combination of the elements in the two sets.

{1, 4, 8, 12}  ∪  {2, 4, 6, 8}

{1, 2, 4, 6, 8, 12}

anygoal [31]3 years ago
3 0

Answer:

{1,2,4,6,8,12}

Step-by-step explanation:

The union means the joining of the sets

{1, 4, 8, 12} U{2, 4, 6, 8}

= {1,2,4,6,8,12}

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Help help please please please
Katarina [22]

Answer:

[?] = 3

Step-by-step explanation:

8 0
3 years ago
The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than
Law Incorporation [45]
Let K=average weight of an okapi and L=that of a llama.
3L=K+190 and K+L=450 so K=450-L. Therefore 3L=450-L+190, 4L=640, L=160kg and K=450-160=290kg.
Okapi weighs 290kg, llama weighs 160kg.
3 0
3 years ago
In △PKQ, PK = KQ = 12, m∠P = 35º. Find PQ.
Neporo4naja [7]

The length of PQ is 19.66 units

Step-by-step explanation:

The given is:

1. PK = KQ = 12

2. m∠P = 35º

We need to find the length pf PQ

∵ PK = KQ

∴ m∠P = m∠Q

∵ m∠P = 35°

∴ m∠Q = 35°

The sum of measures of the angles of a triangle is 180°

∴ m∠P + m∠Q + m∠K = 180°

∴ 35 + 35 + m∠K = 180

∴ 70 + m∠K = 180

- Subtract 70 from both sides

∴ m∠K = 110°

Let us use cosine rule to find the length of PQ

∵ PQ = \sqrt{(KP)^{2}+(KQ)^{2}-2(KP)(KQ)cos(K)}

∵ PK = 12 , KQ = 12 , m∠K = 110°

- Substitute these values in the rule

∴ PQ = \sqrt{(12)^{2}+(12)^{2}-2(12)(12)cos(110)}

∴ PQ = 19.66

The length of PQ is 19.66 units

Learn more:

You can learn more about triangle in brainly.com/question/12985572

#LearnwithBrainly

4 0
4 years ago
Which number is divisible by 2, 3, 4, and 6? a.124 b.3,072 c.1,005 d.786
uysha [10]
I think it might be 124
5 0
3 years ago
Pls help<br><br> Given: △ABC, CM⊥ AB, BC = 5, AB = 7<br> CA = 4 sqrt(2)<br> Find: CM
babymother [125]

Answer:

The general plan is to find BM and from that CM. You need 2 equations to do that.

Step One

Set up the two equations.

(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32

BM^2 + CM^2 = 5^2 = 25

Step Two

Subtract the two equations.

(7 - BM)^2 + CM^2  = 32

BM^2 + CM^2         = 25

(7 - BM)^2 - BM^2 = 7               (3)

Step three

Expand the left side of the new equation labeled (3)

49 - 14BM + BM^2 - BM^2 = 7    

Step 4

Simplify And Solve

49 - 14BM = 7              Subtract 49 from both sides.

-49 - 14BM = 7 - 49

- 14BM = - 42              Divide by - 14

BM = -42 / - 14

BM = 3

Step  Five

Find CM

CM^2 + BM^2 = 5^2

CM^2 + 3^2 = 5^2        Subtract 3^2 from both sides.

CM^2 = 25 - 9            

CM^2 = 16                     Take the square root of both sides.        

sqrt(CM^2) = sqrt(16)

CM = 4    < Answer

Step-by-step explanation:

6 0
3 years ago
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