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Readme [11.4K]
3 years ago
15

Spring tides have higher high tides and lower low tides when the moon, sun, and earth are aligned in a row. Why does this occur?

Physics
2 answers:
stiv31 [10]3 years ago
7 0
"Gravitational pull is stronger" is the one reason among the following choices given in the question why this occurs. he correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that you were looking for and it has come to your desired help.
myrzilka [38]3 years ago
6 0

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

Spring tides occur when the Sun, the Moon and The Earth, all align in the same line. The gravitational pull of the Sun and the Moon, both contribute to the occurrence of these tides. These tides occur twice each lunar month without any regard to the season. Hence, these tides have higher high tides and lower low tides.

Neap tides occur when the Sun and the Moon form right angles with the Earth. The total gravitational pull gets weakened because it acts from two different directions. These occur twice a month. These tides have lower high tides and higher low tides.

Thus, the correct answer is option A.

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A student pulls on a rope attached to a box of books and moves the box down the hall. The student pulls with a force of 185N at
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Answer:

2.75 m/s^2

Explanation:

We can solve the problem by writing the equations of motion along the horizontal and vertical direction.

Along the horizontal direction we have:

T cos \theta - \mu N = ma (1)

where

T cos \theta is the horizontal component of the tension, where

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\theta=25^{\circ} is the angle between the rope and the horizontal

\mu N is the force of friction, where

\mu=0.27 is the coefficient of friction

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Along the vertical direction we have:

N+T sin \theta-mg=0 (2)

where

N is the normal force (upward direction)

T sin \theta is the vertical  component of the tension in the rope (upward direction)

mg is the weight of the box (downward direction), where

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g=9.8 m/s^2 is the acceleration due to gravity

From eq.(2) we get:

N=mg-T sin \theta

And substituting into (1), we can find the acceleration:

T cos \theta - \mu (mg-T sin \theta) = ma\\Tcos \theta -\mu mg + \mu T sin \theta = ma\\a=\frac{T cos \theta- \mu mg + \mu T sin \theta}{m}=\\=\frac{(185)(cos 25^{\circ})-(0.27)(35.0)(9.8)+(0.27)(185)(sin 25^{\circ})}{35.0}=2.75 m/s^2

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Answer:

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