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3 years ago

What happens when a charged insulator is placed near an uncharged metallic object?

2 answers:

8 0

They attract each other.
<span> When the charged insulator (regardless of whether + or -) is brought near an uncharged metallic object, electrons will migrate on the metallic object so that the area near the charged insulator is the opposite charge (and, by conservation of charge, the area of the conducting object away from the insulator will have an excess of the same charge as the insulator).
</span><span> Because opposite charges attract and the opposite charge on the conducting object is closer, the dominant force will be one of attraction.
</span><span> If they are allowed to touch, the conducting object will then have the same charge as the insulator and the objects will repel.</span>

Bad White [126]3 years ago

5 0

<span>So when the charged insulator is placed near the uncharged metallic thing they both attract each other because there will be a distribution of charge between the insulator and uncharged object. This migration of charges happens regardless of their charge positive or negative.</span>

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Which of the following is the smallest in mass?

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3 years ago

A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up

Snezhnost [94]

Answer:

Maximum height of rocket = 2538.74 m

Explanation:

We have equation of motion s = ut + 0.5 at²

For first 5 seconds

s = 0 x 5 + 0.5 x 40 x 5² = 500 m

Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

After 5 seconds velocity of rocket

v = 0 + 40 x 5 = 200 m/s

After 5 seconds the velocity reduces 9.8m/s per second due to gravity.

Time of flying after 5 seconds

$t=\frac{200}{9.81}=20.38s$

Distance traveled in this 20.38 s

s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m

Maximum height of rocket = 500 +2038.74 = 2538.74 m

6 0

3 years ago

A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 newtons. What is the accel

notka56 [123]

Explanation:

F = ma

2 N = (10 kg) a

a = 0.2 m/s²

6 0

3 years ago

If the velocity of a pitched ball has a magnitude of 47.0 m/s and the batted ball's velocity is 50.5 m/s in the opposite directi

Naya [18.7K]

Answer:

The magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $97.5 m$

Explanation:

Given:

Velocity of a pitched ball $v _{i} = 47$ $\frac{m}{s}$

Velocity of ball after impact $v_{f} = -50.5$ $\frac{m}{s}$

From the formula of change in momentum,

$\Delta P = m (v_{f} -v_{i} )$

Here mass is not given in question,

Mass of ball is $m$

Change in momentum is given by,

$\Delta P = m (-50.5 -47)$

$\Delta P = -97.5 m$

Magnitude of change in momentum is

$\Delta P = 97.5 m$

And impulse is given by

$J = \Delta P$

$J = -97.5 m$

So impulse and

Therefore, the magnitude of change in momentum of the ball is $97.5 m$ and impulse is also $-97.5 m$

6 0

3 years ago

Suppose the collision between the packages is perfectly elastic. To what height does the package of mass m rebound?

Hitman42 [59]

The height, h to which the package of mass m bounces to depends on its initial velocity, v and the acceleration due to gravity, g and is given below:

$h = \frac{v^{2}}{2g}$

<h3>What are perfectly elastic collision?</h3>

Perfectly elastic collisions are collisions in which the momentum as well as the energy of the colliding bodies is conserved.

In perfectly elastic collisions, the sum of momentum before collision is equal to the momentum after collision.

Also, the sum of kinetic energy before collision is equal to the sum of kinetic energy after collision.

Since some of the Kinetic energy is converted to potential energy of the body;

$\frac{mv^{2}}{2} = mgh$

$h = \frac{v^{2}}{2g}$

Therefore, the height to which the package m bounces to depends on its initial velocity and the acceleration due to gravity.

Learn more about elastic collisions at: brainly.com/question/7694106

7 0

3 years ago