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ELEN [110]
3 years ago
10

The three ropes in the figure are tied to a small, very light ring. Two of these ropes are anchored to walls at right angles wit

h tensions T1 = 20 N and T2 = 60 N. What are the magnitude and direction of the tension vector T3 in the third rope?
Correct: Your answer is correct. N. ° (below the positive x-axis)
Physics
1 answer:
netineya [11]3 years ago
8 0
<span>Let t be the angle made by T3 with the x-axis.

 T3 * cos(t) = 20 N ---- (1)
 T3 * sin(t) = 60 N ----- (2)

 Square both equations and add:

T3^2 = 20^2 + 60^2 = 400 + 3600 = 4000
T3 = sqrt(4000) = 63.25 N
 
divide (2) by (1):
tan(t) = 60/20 = 3
t = arctan(3) = 71.57 degrees.

</span><span>Since the angle clockwise from the x-axis some books may call it a negative angle and say the angle is -71.57 degrees or round it to -71.6 or even -72 degrees.</span>
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There is a limit to how long your neck can be. If your neck were too long, no blood would reach your brain! What is the maximum
spayn [35]

Answer:

The maximum height a person's brain could be above his heart is: 1.28 meter.

Explanation:

We need to know what is the normal blood pressure ours hearts so there is a rate: 120/80 (mmHg) and the average will be: 100 (mmHg) and using the Pascal law that relate pressure, density, gravity and height like:P_{2} = pgh_{1} - pgh_{2} + P_{1}, where P is pressure, p is density, g is the gravity acceleration and h is the height. Now we can find the height and delta of pressure will be: P2-P1 = 100 (mmHg), knowing that 1(mmHg) is equal to 133 Pa, we can do the convertion to 13332.2 (Pa), now because the units of Pascal are Newton/(meter^2). Then we solve the formula to get the height: \frac{P2-P1}{pg} =h so we get:\frac{13332.2}{(1060*9,81)}=Height=1.28(meters).

5 0
3 years ago
Determine the magnitude of the component of F directed along the axis of AB. Set F = 520 N .
Soloha48 [4]

Answer:

The component of F along AB is equal to Fcos45

F = 520N

Component along AB = 520cos45

= 367.7N

This is done by rotating the diamonds such that AB is now taken as the x-axis. Then the force F is resolved along AB.

Explanation:

7 0
3 years ago
Read 2 more answers
What potential difference is required to cause 4.00 a to flow through a resistance of 330 ω?
Alisiya [41]
We can solve the problem by using Ohm's law, which states that an Ohmic conductor the following relationship holds:
\Delta V = I R
where
\Delta V is the potential difference applied to the resistor
I is the current flowing through it
R is the resistance

In our problem, I=4.00 A and R=330 \omega, so the potential difference is
\Delta V = IR=(4.00 A)(330 \omega)=1320 V
7 0
3 years ago
While finding the spring constant, if X1 = 12 cm, X2 = 15 cm, and hanging mass = 22 grams, the value of spring constant K would
Pavel [41]

Answer:

If x₁=12 cm then k=1.7985 N/m

If x₂=15 cm then k=1.4388 N/m

Explanation:

Hanging mass= 22 g=0.022 kg

Acceleration due to gravity g=9.81 m/s²

If x₁=displacement= 12 cm=0.12 m

k= spring constant

F=ma\\\Rightarrow F=0.022\times 9.81\\\Rightarrow F=0.21582\ N

\text {For spring}\\F=kx\\\Rightarrow 0.21582=k\times 0.012\\\Rightarrow k=1.7985\ N/m\\

∴k = 1.7985 N/m

If x₂=15 cm=0.15 m

Force of the hanging mass is same however the spring constant will change

\text {For spring}\\F=kx\\\Rightarrow 0.21582=k\times 0.015\\\Rightarrow k=1.4388\ N/m\\

∴k = 1.4388 N/m

As the mass is not changing the spring constant has to change. That means that here there are two spring one with k=1.7985 N/m and the other with k= 1.4388 N/m

4 0
3 years ago
A parallel circuit has a 125 Volt battery connected with 3 resistors. R1= 20 Ω, R2= 100 Ω, and R3= 50 Ω. Find the total current
Musya8 [376]

Answer:

10A

Explanation:

to calculate r

1/R=1/20+1/100+1/50=2/25

r=25/2=12.5

I=125/12.5=10A

8 0
3 years ago
Read 2 more answers
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