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Ronch [10]
3 years ago
13

So, how do owls live. Like I need a serious explanation food,water,sleeping,predators,prey. Or give me all you know. But somethi

ng!
Mathematics
2 answers:
pashok25 [27]3 years ago
6 0

<span>Owls are found in many different habitats, such as deserts, forests, prairies and even the Arctic tundra. They nest in trees, in holes in the ground, in barns, and in caves. And while many other birds migrate to warmer places during the winter, most owls do not. They live in the same place all year round.</span>
scoundrel [369]3 years ago
4 0
Well they need food water shelter they need to saty and a worm place so they wont freeze
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NEED HELP ASAP PLEASE!!
inna [77]
The correct answer should be C
7 0
3 years ago
Can someone help me with this
lozanna [386]

Answer:

the answer is 2.5 which in not greater than 6 but less than 5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6
Anton [14]

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

V= \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder,x^{2}+y^{2} =1 and the ellipsoid, 4x^{2}+ 4y^{2} + z^{2} =64

In polar coordinates, we know that

x^{2}+y^{2} =r^{2}

So, the ellipsoid gives

4{(x^{2}+ y^{2)} + z^{2} =64

4(r^{2}) + z^{2} = 64

z^{2} = 64- 4(r^{2})

z=± \sqrt{64-4r^{2} }

So, the volume of the solid is given by:

V= \int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta

= 2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta

To solve the integral take, 64-4r^{2} = t

dt= -8rdr

rdr = \frac{-1}{8} dt

So, the integral  \int\ r\sqrt{64-4r^{2} } rdr become

=\int\ \sqrt{t } \frac{-1}{8} dt

= \frac{-1}{12} t^{3/2}

=\frac{-1}{12} (64-4r^{2}) ^{3/2}

so on applying the limit, the volume becomes

V= 2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta

=\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta

V = \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Since, further the integral isn't having any term of \theta.

we will end here.

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0
1 year ago
James has mapped his seat and his teacher's seat on the coordinate plane at (0,10) and (–4,6). Find the distance between their s
pshichka [43]

Answer:

4√2 units (Answer C).

Step-by-step explanation:

Going from the seat at (-4,6) to the one at (0,10), x increases by 4 units and y increases by 4 units.  We need to use the distance formula to determine how far apart these seats are.

d = √(change in x)^2 + (change in y)^2 ).

That works out to:

d = √(4^2 + 4^2) = √(32) = 4√2 units (Answer C).

8 0
3 years ago
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Mr Bartley is taking the theater club
PtichkaEL [24]
What is he doing behind stage
8 0
3 years ago
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