Answer:
#include <iostream>
using namespace std;
void divide(int numerator, int denominator, int *quotient, int *remainder)
{
*quotient = (int)(numerator / denominator);
*remainder = numerator % denominator;
}
int main()
{
int num = 42, den = 5, quotient=0, remainder=0;
divide(num, den, "ient, &remainder);
return 0;
}
Explanation:
The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.
To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.
Thanks! :)
Answer:
=AND($C11 = "Yes", $D11 = "Yes")
Explanation:
The AND function takes conditional inputs and tests if each of them are TRUE. If all of the inputs are TRUE, the function will output TRUE but if any one of them are not the function will output FALSE. This scales to multiple inputs but this example only has two conditions. It is important to remember that we want to compare a string so our condition must be "Yes", not just Yes.
We also use a relative cell reference, "$", on the columns C and D since we always want to use the "Runner on 1st" and "Runner on 2nd" columns.
Answer:
c) 10.
Explanation:
The script will return 10 after the user enters 5 at both prompts.In the script we have three variables firstNumber,secondNumberand thirdNumber.Where the user is entering the values in the firstNumber and the secondNumber and thirdNumber stores the sum of firsNumber and secondNumber and after that it writes on the web page using the document.write.
