293 tens and 4 ones
<em>Explanation:
</em>If you have 293 tens you have 2930 already.
293*10 = 2930
Now you are only missing 4,
4*1 = 4
so you can use 4 ones
Answer:
1. x = +/- 2
- 7
2. x =
+/- 
3. n =
+/- 
Step-by-step explanation:
1. Divide both sides by 2: (x + 7)^2 = 8
Square root both sides: x + 7 = +/- 2
Subtract 7 from both sides: x = +/- 2
- 7
2. Square root both sides: x - 3 = 
Since there is a negative inside the radical, we need to have an imaginary number:
. So, 
Add 3 to both sides: x =
+/- 
3. Divide by -5 from both sides: (n - 2)^2 = -2
Square root both sides: n - 2 = 
Again, we have to use i: 
Add 2 to both sides: n =
+/- 
Hope this helps!
Answer:,
the answer is (4,2)
Step-by-step explanation:
is you look at the 2 equations and plug in the points where the lines intercets you would get the answer soo examples
4+2=6
the first one checks out
the second one
4+(2*2)=8
so the parinthises go first 2 times 2 = 4 plus 4 = 8