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defon
3 years ago
14

Why should you follow-up with your interviewer after a job interview?

Computers and Technology
2 answers:
elixir [45]3 years ago
8 0

B. To reinforce your interest in the position and thank your interviewer


Nana76 [90]3 years ago
7 0

Answer:

B

Explanation:

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HELP ME ASAP PLS BEING TIMED
kkurt [141]

Answer:

It would be considered cheating.

Explanation:

Any type of electronic use is considered cheating because you can look up the answers on the same phone or text someone for the answer. And so, Text messaging during a test is cheating because of the fact that is convenient to the cheater and not convenient to the teacher that is grading.

8 0
4 years ago
Read 2 more answers
Which phone has the most GB (Gigo Bites)<br><br>A.Samsung<br>B.Iphone<br>C.LG<br>D.ZTE
Lina20 [59]
It's GigaBytes actually. And is it RAM or storage capabilities?

And also those are brands. Not models. For example, Samsung has different phones. Not just one.


7 0
3 years ago
Read 2 more answers
Anyone knows how to do this??
a_sh-v [17]
I dont know how to do that
4 0
3 years ago
The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
4 years ago
What is the value of the num_colors variable? var colors = ["red","blue","orange","yellow","green","brown","purple"]; num_colors
barxatty [35]

Answer:

Hello the options to your question is missing here are the options

  • 6
  • 7
  • 8
  • NaN

answer : 7

Explanation:

The value of the num_colors variable is 7 and this because you have to neglect the fact that there is no termination symbol at the end of the assignment operation in the code.

But when we consider the none existence of a termination symbol at the end of the assignment operation in the code, the code will generate a syntax error instead of a value.

4 0
3 years ago
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