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ludmilkaskok [199]
3 years ago
8

How to solve v+8/9=10

Mathematics
2 answers:
kati45 [8]3 years ago
8 0
First subtract 8/9 from both sides
now you have v = 10-8/9
if you can leave it as a fraction, 90/9-8/9 = 82/9 = v=9 1/9

Dovator [93]3 years ago
6 0
<span>v+<span>8/9</span></span>=<span>10

=v+8/9-8/9=10-8/9

= v=82/9

Answer is v=82/9
</span>
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Answer:

y >   \boxed{\cfrac{42}{5} }

Step-by-step explanation:

Given inequality:

\cfrac{y}{3} > 7 - \cfrac{y}{2}

To solve for <em>y.</em>

Solution:

Rewrite the inequality as,

  • \displaystyle \frac{1y}{3}  >   \frac{ - 1}{2} y + 7

Adding 1/2y to both sides,

  • \cfrac{1}{3} y +  \cfrac{ 1 }{2} y >  \cfrac{ - 1}{2}y  + 7 +  \cfrac{1}{2} y

  • \cfrac{5}{6} y > 7

Multiplying both sides by 6/5:

  • \cfrac{6}{5}  \times  \cfrac{5}{6} y >  \cfrac{6}{5}  \times 7

  • y >   \boxed{\cfrac{42}{5} }

Value of y is 42/5.

7 0
2 years ago
USE THE FREQUENCY DISTRIBUTION TO DETERMINE THE FOLLOWING:A) THE TOTAL NUMBER OF OBSERVATIONS.B) THE WIDTH OF EACH CLASS.C) THE
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A) The total number is the sum of all the frequencies

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B) The width is (upper limit - lower limit) / 2

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(50-36) / 2 = 7

(65-51) / 2 = 7

(80-66) / 2 = 7

(95-81) / 2 = 7

(110-96) / 2 = 7

Answer: the width is 7

C) The midpoint is the lower limit + the width

36+7=43

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D)The modal is the class with more frequency

In this case 66-80 with 12

Answer: class 66-80

E) We use the width formula

lower limit = 111

width = 7

upper = (width * 2) - lower

upper = (7 * 2) + 111

upper = 125

Answer: class 111-125

4 0
1 year ago
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