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Alex17521 [72]
3 years ago
6

The ________ method displays a message to the user and contains one button.

Computers and Technology
1 answer:
jolli1 [7]3 years ago
6 0
<span>The <em><u>message box</u></em> method displays a message to the user and contains one button.</span>
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python A pet shop wants to give a discount to its clients if they buy one or more pets. The discount is equal to 20 percent of t
Artyom0805 [142]

Answer:

The following are the program in the Python Programming Language.

#define function

def discount(prices, isPet, nItems):

 # declare and initialize variables to 0

 i = 0

 cost = 0

 pets = 0

 item = 0

 item_Cost = 0

 #set the while loop

 while(i < nItems):

   #check the items of the variable

   if isPet[i]:

     #add and initialize in the cost

     cost += prices[i]

     #increament in the variable by 1

     pets += 1

   #otherwise

   else:

     #add and initialize in the item_Cost

     item_Cost += prices[i]

     #increament in the variable by 1

     item += 1

   #then increment in the variable by 1

   i += 1

 #check the pet is greater than equal to 1  

 #and item is greater than equal to 5

 if(pets >= 1 and item >=5):

   #then, print the message

   print("You receive discount")

   #set discount of the items

   discount = 0.2 * item_Cost

   # calculate bill after deducting discount

   bill = cost + item_Cost - discount

   #print the bill

   print("Final Bill amount is", bill)

 #otherwise

 else:

   #print the message

   print("You do not receive any discount")

   #calculate bill without deducting discount

   bill = cost + item_Cost

   #print the final bill

   print("Final Bill amount is", bill)

#set empty list type variables

price = []

pet = []

#set the infinite loop

while True:

 #get input from the user

 sprice = int(input("Enter the price (-1 to quit): "))

 #check that price is not equal to the -1

 if(sprice != -1):

   #add price in the list

   price.append(sprice)

   #ask for choice from the user

   choice = input("Is it a pet (Y / N)? ")

   #check the choice of the user is y or Y

   if(choice == 'Y' or choice == 'y'):

     # then, add in the pet

     pet.append(True)

   #otherwise

   else:

     #not add in the pet

     pet.append(False)

   print("")

 #break the loop

 else:

   break

#declare variable that store the length

items = len(price)

#call and initialize the variable

discount(price, pet, items)

<u>Output</u>:

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? y

Enter the price (-1 to quit): 69

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 41

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 52

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 96

Is it a pet (Y / N)? n

Enter the price (-1 to quit): 74

Is it a pet (Y / N)? n

Enter the price (-1 to quit): -1

You receive discount

Final Bill amount is 361.6

Explanation:

<u>The following are the description of the program</u>.

  • Firstly, define the function 'discount()' and pass the arguments 'prices', 'isPet' and 'nItems' in its parameter.
  • Then, declare and initialize the variables 'i' to 0, 'item_Cost' to 0
  • , item to 0, 'cost' to 0 and 'pets' to 0.
  • Then, set the while loop to add the price of the items and the cost of the pets.
  • Set the if-else conditional statement to check the pet is greater than equal to 1 and the items are greater than equal to 5 then, set the discount and print the bill after deduction.
  • Otherwise, print the bill without deduction.
  • Finally, set two list type variable then, set the infinite while loop that gets input from the user and check that the variable is not equal to -1 then append the data in the list then again check the user input then append in pet otherwise not append in pet and break the loop. Then, set the variable that stores the length of the price and call the following function by passing arguments in its parameter.
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3 years ago
Help please not trying to fail
deff fn [24]

Answer:

B. Everywhere CFCI is not

8 0
3 years ago
what are the main technologies that have contributed to be growth and commercialization of the Internet
iren [92.7K]

hope it helps have a good day

5 0
2 years ago
Which statement is correct? a. choice of metric will influence the shape of the clusters b. choice of initial centroids will inf
katrin2010 [14]

Answer: the answer is c

Explanation:in general, the merges and splits in hierarchical clustering are determined in a greedy manner

8 0
3 years ago
The OSI model is a useful tool in troubleshooting a network because it enables you to isolate a problem to a particular software
lutik1710 [3]

Answer:

1)  Layer 4, transport

2) Layer 2, datalink

3) Layer 5, session

4) Layer 7, application

Description of Problems are as below:

1) One of your servers has been exhibiting sluggish network performance. you use a network-monitoring program to try to evaluate the problem. You find considerable TCP retries occurring because the server is being overwhelmed by data, and packets are being discarded.

2) You check some statistics generated by a network-monitoring program and discovers that an abnormally high number of CRC errors were detected. (Hint think of the cause of CRC errors).

3) A user is trying to connect to another computer, but the logon attempt is continually rejected.

4) You try to access a Linux server to share files by using NFS. You can communicate with the server, but the shared files don't appear to be available.

Explanation:

OSI Model is a reference model to determine how applications communicate over a network. OSI consists of seven layers, and each layer performs a particular network function. The seven layers are:

   Layer 7 - Application.

   Layer 6 - Presentation.

   Layer 5 - Session.

   Layer 4 - Transport.

   Layer 3 - Network.

   Layer 2 - Data Link.

   Layer 1 - Physical.

1) One of your servers has been exhibiting sluggish network performance. you use a network-monitoring program to try to evaluate the problem. You find considerable TCP retries occurring because the server is being overwhelmed by data, and packets are being discarded.

Layer 4, transport

2) You check some statistics generated by a network-monitoring program and discovers that an abnormally high number of CRC errors were detected. (Hint think of the cause of CRC errors).

Layer 2, Data Link

3) A user is trying to connect to another computer, but the logon attempt is continually rejected.

Layer 5, session

4) You try to access a Linux server to share files by using NFS. You can communicate with the server, but the shared files don't appear to be available.

Layer 7, application

7 0
3 years ago
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