Answer:
inductance of the coil 29.3767 H
Explanation:
given data
resistor R = 19.0 kΩ = 19 × 10³ Ω
potential applied V = 50.0 V
current I = 2.20 mA = 2.20 × 
A
time t = 2.80 ms = 2.80 × s
solution
we know for maximum current in circuit that is
current = V ÷ R .........1
current = 
current = 2.63 × A
so at time t = 0
t = 
L = 29.3767
Electrons need specific amount of energy to jump levels and to emit energy
Answer:
The resistance of the tungsten coil at 80 degrees Celsius is 15.12 ohm
Explanation:
The given parameters are;
The resistance of the tungsten coil at 15 degrees Celsius = 12 ohm
The temperature coefficient of resistance of tungsten = 0.004/°C
The resistance of the tungsten coil at 80 degrees Celsius is found using the following relation;
R₂ = R₁·[1 + α·(t₂ - t₁)]
Where;
R₁ = The resistance at the initial temperature = 12 ohm
R₂ = The resistance of tungsten at the final temperature
t₁ = The initial temperature = 15 degrees Celsius
t₂ = The final temperature = 80 degrees Celsius
α = temperature coefficient of resistance of tungsten = 0.004/°C
Therefore, we have;
R₂ = 12×[1 + 0.004×(80 - 15)] = 15.12 ohm
The resistance of the tungsten coil at 80 degrees Celsius = 15.12 ohm.
Answer:
Explanation:
Given that there are boys (plural) only at a height of 3 meters, they still might have more energy than a single girl.
The girl might have a mass of 50 to 60 kg. The boys will likely have slightly more.
Girl PE
PE = 5 * 50 * 10
PE = 2500 N
Boys
PE = 3 * 120 * 10
PE = 3600 N
That's with 2 boys on the 3 meter board. The girl would have a PE more than 1 boy likely or possibly.
