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antiseptic1488 [7]
3 years ago
8

Why do X-Ray technicians stand behind a shield when giving X-Rays to patients? A) because large doses of X-Rays cause blindness

B) because they can more accurately see the patient's bones C) because they need to protect themselves from patient disease D) because large doses of X-Rays are known to cause cell damage and cancers
Physics
2 answers:
mezya [45]3 years ago
7 0
Your answer is D, large doses of the radiation given off from x rays has been known to causes cell damage which can lead to cancer.
let me know if you have any other questions
:)
Likurg_2 [28]3 years ago
6 0

X-ray technicians stand behind a shield when giving X-rays to patients because large doses of X-rays are known to cause cell damage and cancers.

Answer: D

Explanation:

Electromagnetic radiations like x-rays, alpha rays and other cosmic rays are harmful to human health and tissues to some extent when it is exposed for long time.

The x-rays are created when highly accelerated electrons hit the metal leading to ejection of electrons from its shell.

The x-rays are highly penetrate able but it cannot penetrate bones. So it is mostly used for getting scans of bones.

X-rays can penetrate cells and when exposed for large time in large doses it can harm the cell by damaging them or by creating cancer cells.

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Explain why some people see objects nearby clearly, but objects far away appear blurry. Also, explain how this condition can be
Maru [420]

Myopia

Explanation:

myopia is a common vision condition in which you can see objects near to you clearly, but objects farther away are blurry. It occurs when the shape of your eye causes light rays to refract incorrectly, focusing images in front of your retina instead of on your retina. It can be corrected corrected with eyeglasses, contact lenses or refractive surgery.

7 0
3 years ago
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The national government would like to start a program that would give states money for flood relief. Which of the following stat
rewona [7]

Answer:

When a disaster is declared, the Federal government, led by the Federal Emergency Management Agency (FEMA), responds at the request of, and in support of, States, Tribes, Territories, and Insular Areas and local jurisdictions impacted by a disaster.

Explanation:

3 0
2 years ago
2. The ability to keep<br> upright posture while standing or moving
Masteriza [31]
Is balancing .
Hope this is helpful
4 0
3 years ago
An object has traveled 20 meters in 40 seconds what is its average speed
Mice21 [21]

Hello,


To solve we need to know the formula for speed

The formula is D/T=S     (Distance of time=speed)

Now all we have to do is plug in the numbers.

20/40= 1/2 or 0.5

SO the speed is 0.5 m/s


Have a great day!

6 0
3 years ago
Consider a uniform horizontal wooden board that acts as a pedestrian bridge. The bridge has a mass of 300 kg and a length of 10
gayaneshka [121]

Answer:

F = 2123.33N

Explanation:

In order to calculate the torque applied by the left support, you take into account that the system is at equilibrium. Then, the resultant of the implied torques are zero.

\Sigma \tau=0

Next, you calculate the resultant of the torques around the right support, by taking into account that the torques are generated by the center of mass of the wooden, the person and the left support. Furthermore, you take into account that torques in a clockwise direction are negative and in counterclockwise are positive.

Then, you obtain the following formula:

-\tau_l+\tau_p+\tau_{cm}=0          (1)

τl: torque produced by the left support

τp: torque produced by the person

τcm: torque produced by the center of mass of the wooden

The torque is given by:

\tau=Fd           (2)

F: force applied

d: distance to the pivot of the torque, in this case, distance to the right support.

You replace the equation (2) into the equation (1) and take into account that the force applied by the person and the center of mass of the wood are the their weight:

-Fd_1+W_pd_2+W_{cm}d_3=0\\\\d_1=6.0m\\\\d_2=2.0m\\\\d_3=3.0m\\\\W_p=(200kg)(9.8m/s^2)=1960N\\\\W_{cm}=(300kg)(9.8m/s^2)=2940N

Where d1, d2 and d3 are distance to the right support.

You solve the equation for F and replace the values of the other parameters:

F=\frac{W_pd_2+W_d_3}{d_1}=\frac{(1960N)(2.0m)+(2940N)(3.0m)}{6.0m}\\\\F=2123.33N

The force applied by the left support is 2123.33 N

8 0
3 years ago
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