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Sergio [31]
3 years ago
12

(Power Cycle)​ Your new boss announces at a team meeting that she has developed atechnology that will perform a power cycle that

operates between hot and cold reservoirs at 902 °C and 22 °C that produces a power output of 28 kW while receiving 150,000 kJ/hof energy via heat transfer from the hot reservoir. You are suspicious that this cyclesounds too good to be true, so you decide to check. What do you find
Physics
1 answer:
Angelina_Jolie [31]3 years ago
8 0

Answer:

answered

Explanation:

The maximum possible efficiency is  

\eta= 1-\frac{T_L}{T_H}

\eta= 1-\frac{295}{1175}

= 0.7489

W_out= 28 KW

Q_in= 15000/3600= 41.67 KW

now

\eta= \frac{W_out}{Q_H}

\eta= \frac{28}{41.67} =0.6791

which is less than \eta_{max}

claim is true

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A heat pump absorbs heat from the atmosphere at a rate of 30 kW. If work is being done to run this heat pump at a rate of 7.7 kW
Volgvan

Answer:

Option D 3.9

Explanation:

First, you need to use the correct equation which is the following:

COP = Q/W

Where:

Q = heat absorbed

W = work done by the pump

COP = coefficient of perfomance

We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:

COP = 30 / 7.7

COP = 3.896

This result you can round it to 3.9. option D.

8 0
3 years ago
It's important to do cardiovascular exercise on a regular basis because it _____.
n200080 [17]

Answer:

I believe it improves your hearts stroke volume

If im wrong plz let me know

4 0
3 years ago
1-Find the gravitational force
butalik [34]

g = \frac{GMm}{r^2}

where G is the gravitational constant and is about 6.67 * 10^{-11}

g = \frac{6.67 * 10^{-11} * 25 * 0.55}{35^2}

g = \frac{6.67 * 10^{-11} * 25 * 0.55}{1225} = 0.000000000000749 N :D

5 0
3 years ago
Why is stepping on a can considered a physical change?
melisa1 [442]
Stepping on a can is a physical change because there is no chemistry behind this. Someone is physically breaking or deforming the can. There are no chemicals or anything touching the can. The foot smashing is physical. 
4 0
3 years ago
ASK YOUR TEACHER A 2.0-kg mass swings at the end of a light string with the length of 3.0 m. Its speed at the lowest point on it
Nadya [2.5K]

Answer:

  K_b = 78 J

Explanation:

For this exercise we can use the conservation of energy relations

starting point. Lowest of the trajectory

        Em₀ = K = ½ mv²

final point. When it is at tea = 50º

        Em_f = K + U

        Em_f = ½ m v_b² + m g h

where h is the height from the lowest point

        h = L - L cos 50

        Em_f = ½ m v_b² + mg L (1 - cos50)

energy be conserve

        Em₀ = Em_f

         ½ mv² = ½ m v_b² + mg L (1 - cos50)

         K_b = ½ m v_b² + mg L (1 - cos50)

let's calculate

          K_b = ½ 2.0 6.0² + 2.0 9.8 6.0 (1 - cos50)

          K_b = 36 +42.0

          K_b = 78 J

4 0
3 years ago
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