From tables, the speed of sound at 0°C is approximately
V₁ = 331 m/s (in air)
V₃ = 5130 m/s (in iron)
Distance traveled is
d = 100 km = 10⁵ m
Time required to travel in air is
t₁ = d/V₁ = 10⁵/331 = 302.12 s
Time required to travel in iron is
t₂ = d/V₂ = 10⁵/5130 = 19.49 s
The difference in time is
302.12 - 19.49 = 282.63 s
Answer: 283 s (nearest second)
Answer:
life (N) of the specimen is 117000 cycles
Explanation:
given data
ultimate strength Su = 120 kpsi
stress amplitude σa = 70 kpsi
solution
we first calculate the endurance limit of specimen Se i.e
Se = 0.5× Su .............1
Se = 0.5 × 120
Se = 60 kpsi
and we know strength of friction f = 0.82
and we take endurance limit Se is = 60 kpsi
so here coefficient value (a) will be
a =
......................1
put here value and we get
a =
a = 161.4 kpsi
so coefficient value (b) will be
b =
b =
b = −0.0716
so here number of cycle N will be
N = 
put here value and we get
N = 
N = 117000
so life (N) of the specimen is 117000 cycles
The CORRECT answer would be false. They are different and so therefore the answer is false.
Hope this helped ‼️
Answer:
Explanation:
Let x ft be used to make square and 2-x ft be used to make equilateral triangle.
each side of square = x/4
area of square = ( x /4 )²
Each side of triangle
= (2-x) /3
Area of triangle = 1/2 (2-x)²/9 sin 60
= √3 / 36 x (2-x)²
Total area
A = ( x /4 )² +√3 / 36 (2-x)²
For maximum area
dA/dx = 0
1/16( 2x ) -√3 / 36 x2(2-x) = 0
x / 8 - √3(2-x)/ 18 = 0
x / 8 - √3/9 + √3/18 x = 0
x ( 1/8 + √3/18 ) = √3/9
x(.125 +.096 ) = .192
x = .868 ft