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Pavel [41]
4 years ago
14

Elastic recovery: a. Is the strain that remains in a material when it is deformed plastically, then unloaded. b. Is the strain t

hat occurs when a material is loaded elastically, then unloaded. c. Is the difference between the strain right before unloading and the strain that remains after unloading. d. None of the above.
Engineering
1 answer:
Artyom0805 [142]4 years ago
7 0

Answer:

d.

Explanation:

Elastic recovery is the ability of the elastomer to return to its original shape after the  compression load has been removed.

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What happens to the amperage draw of a condensing unit on a split AC system if the liquid line is restricted
cupoosta [38]

Answer:

The amperage draw of the condensing unit will be low.

Explanation:

A condensing unit is made up of a compressor and condenser, while an evaporating unit is made up of an evaporator coil.

A split AC system is a type of air conditioner system that has a condensing unit which is placed separately from the evaporative coil unit. Then the two units are connected to each other via a copper tube containing refrigerants.

The liquid line connects the condenser to the evaporator, and if this liquid line is restricted, the amp consumed by the condensing unit will be low.

6 0
3 years ago
1 gallon of benzene having a density of 0.88 g/mL is spilled in 200 feet by 150 foot lake having an average depth of 6 feet. Wha
Irina18 [472]

Answer:

The concentration of benzene in this contaminated lake would be 653549ng/L.

Explanation:

The concentration C of a contaminant over a body of water of volume V can be obtained as:

C=Mass contaminant / V

In this case, the volume of the body of water:

V=200ft\cdot150ft\cdot6ft=5097.033m^3

The mass of the contaminant (Benzene):

m=\delta V_{ben}=0.88\frac{g}{ml} 1gal(us)=3.3311kg

Therefore:

C=\frac{m_{ben}}{V_{lake}}=6.53549\cdot10^{-4}kg/m^3=653549ng/l

4 0
4 years ago
How meny people live in new york
nydimaria [60]

Answer:

8.419 million (2019) at 2019

4 0
3 years ago
Suppose you have two arrays: Arr1 and Arr2. Arr1 will be sorted values. For each element v in Arr2, you need to write a pseudo c
brilliants [131]

Answer:

The algorithm is as follows:

1. Declare Arr1 and Arr2

2. Get Input for Arr1 and Arr2

3. Initialize count to 0

4. For i in Arr2

4.1 For j in Arr1:

4.1.1 If i > j Then

4.1.1.1 count = count + 1

4.2 End j loop

4.3 Print count

4.4 count = 0

4.5 End i loop

5. End

Explanation:

This declares both arrays

1. Declare Arr1 and Arr2

This gets input for both arrays

2. Get Input for Arr1 and Arr2

This initializes count to 0

3. Initialize count to 0

This iterates through Arr2

4. For i in Arr2

This iterates through Arr1 (An inner loop)

4.1 For j in Arr1:

This checks if current element is greater than current element in Arr1

4.1.1 If i > j Then

If yes, count is incremented by 1

4.1.1.1 count = count + 1

This ends the inner loop

4.2 End j loop

Print count and set count to 0

<em>4.3 Print count</em>

<em>4.4 count = 0</em>

End the outer loop

4.5 End i loop

End the algorithm

5. End

6 0
3 years ago
A) For Well A, provide a cross-section sketch that shows (i) ground elevation, (ii) casing height, (iii) depth to
Ad libitum [116K]
Don’t go on that file will give a virus! Sorry just looking out and I don’t know how to comment!
7 0
3 years ago
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