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3 years ago

Discuss why you should not use an electrical tool that has a patch or taped cord

Engineering

1 answer:

IgorC [24]3 years ago

4 0

Answer:

If we were to wrap an electrical cord with electrical tape, it could significantly change the flexibility characteristics of the cord, which in turn can affect the amount of stress in the areas adjacent to the tape; this is particularly a concern with respect to the proper function of the grounding wire

Read more here:

brainly.com/question/15220801

5 0

3 years ago

Design a logic circuit that has a 4-bit binary number as an input and one output. The output should be 1 iffthe input is a prime

Maurinko [17]

Answer:

Check the explanation

Explanation:

Solution

Let the $L_1$ binary input one A,B,C,D and output is F with $L_1$ binary inputs we have $16=2^4$ combination as in below.

Kindly check the attached image below to get the full step by step explanation to the question above.

5 0

4 years ago

Consider a 8-m-long, 8-m-wide, and 2-m-high aboveground swimming pool that is filled with water to the rim. (a) Determine the hy

Stolb23 [73]

Answer:

The hydrostatic force of 313920 N is acted on each wall of the swimming pool and this force is acted at 1 m from the ground. The hydrostatic force is quadruple if the height of the walls is doubled.

Explanation:

To calculate force on the walls of swimming pool whose dimensions are given as 8-m-long, 8-m-wide, and 2-m-high. We know that formula for hydrostatic force is $\text {hydrostatic force}=\text {pressure} \times \text {area,}=\rho g h \times(l \times h)$

$\equiv \rho g h^{2} l$ , we know ρ=density of fluid=1000 $g / c m^{3}$ ,

g=acceleration due to gravity=9.81 $m / s^{2}$ , h=height of the pool=2 m and l=length of the pool=8 m.

hydrostatic force on each wall= $1000 \times 9.81 \times 2^{2} \times 8$ = 313920 N.

The distance at which hydrostatic force is acted is half of the height of the swimming pool.

At 1 m from the ground this hydrostatic force is acted on each wall.

The force is quadruple if the height of the walls of the pool is doubled this is because, the height is doubled and taken as h=4 m and substitute in the equation = $\rho g h^{2} l$ = $1000 \times 9.81 \times 4^{2} \times 8$ = 1255680 N. This is 4 times 313920 N.

5 0

3 years ago

A fully charged battery with 6 cells should indicate

finlep [7]

Answer:

Battery Voltage

Voltage refers to the amount of electrical potential your battery holds. The standard automotive battery in today's vehicles is a 12-volt battery. Each battery has six cells, each with 2.1 volts at full charge. A car battery is considered fully charged at 12.6 volts or higher.

7 0

3 years ago

An equilibrium mixture of 3 kmol of CO, 2.5 kmol of O2, and 8 kmol of N2 is heated to 2600 K at a pressure of 5 atm. Determine t

garri49 [273]

Answer:

$x_{CO}=0.0203\\x_{O_2}=0.0926\\x_{CO_2}=0.227\\x_{N_2}=0.660$

Explanation:

Hello,

In this case, we consider the reaction:

$CO(g)+\frac{1}{2} O_2(g)\rightleftharpoons CO_2$

For which the law of mass action is expressed as:

$Kp=\frac{n_{CO_2}}{n_{CO}*n_{O_2}^{1/2}} (\frac{P}{n_{Tot}} )^{1-1-1/2}$

Whereas the exponents are referred to the stoichiometric coefficients in the chemical reaction. Moreover, in table A-28 (Cengel's thermodynamics) the natural logarithm of the undergoing reaction at 2600 K is 2.801, thus:

$K=exp(2.801)=16.46$

In such a way, in terms of the change $x$ the equilibrium goes:

$16.46=\frac{x}{(3kmol-x)*(2.5kmol-0.5x)^{0.5}} (\frac{5}{13.5kmol-0.5x} )^{-0.5}$

Hence, solving for $x$ :

$x=2.754kmol$

Thus, the moles at equilibrium:

$n_{CO}=3-2.754=0.246kmol\\n_{O_2}=2.5-0.5(2.754)=1.123kmol\\n_{CO_2}=x=2.754kmol\\n_{N_2}=8kmol$

Finally the compositions:

$x_{CO}=\frac{0.246}{0.246+1.123+2.754+8} =0.0203\\\\x_{O_2}=\frac{1.123}{0.246+1.123+2.754+8} =0.0926\\\\x_{CO_2}=\frac{2.754}{0.246+1.123+2.754+8} =0.227\\\\x_{N_2}=\frac{8}{0.246+1.123+2.754+8} =0.660$

Best regards.

7 0

4 years ago