Answer:
Minimum electrical power required = 3.784 Watts
Minimum battery size needed = 3.03 Amp-hr
Explanation:
Temperature of the beverages, ![T_L = 36^0 F = 275.372 K](https://tex.z-dn.net/?f=T_L%20%3D%2036%5E0%20F%20%3D%20275.372%20K)
Outside temperature, ![T_H = 100^0F = 310.928 K](https://tex.z-dn.net/?f=T_H%20%3D%20100%5E0F%20%3D%20310.928%20K)
rate of insulation, ![Q = 100 Btu/h](https://tex.z-dn.net/?f=Q%20%3D%20100%20Btu%2Fh)
To get the minimum electrical power required, use the relation below:
![\frac{T_L}{T_H - T_L} = \frac{Q}{W} \\W = \frac{Q(T_H - T_L)}{T_L}\\W = \frac{100(310.928 - 275.372)}{275.372}\\W = 12.91 Btu/h\\1 Btu/h = 0.293071 W\\W = 12.91 * 0.293071\\W_{min} = 3.784 Watt](https://tex.z-dn.net/?f=%5Cfrac%7BT_L%7D%7BT_H%20-%20T_L%7D%20%3D%20%5Cfrac%7BQ%7D%7BW%7D%20%5C%5CW%20%3D%20%5Cfrac%7BQ%28T_H%20-%20T_L%29%7D%7BT_L%7D%5C%5CW%20%3D%20%5Cfrac%7B100%28310.928%20-%20275.372%29%7D%7B275.372%7D%5C%5CW%20%3D%2012.91%20Btu%2Fh%5C%5C1%20Btu%2Fh%20%3D%200.293071%20W%5C%5CW%20%3D%2012.91%20%2A%200.293071%5C%5CW_%7Bmin%7D%20%3D%203.784%20Watt)
V = 5 V
Power = IV
![W_{min} = I_{min} V\\3.784 = 5I_{min}\\I_{min} = \frac{3.784}{5} \\I_{min} = 0.7568 A](https://tex.z-dn.net/?f=W_%7Bmin%7D%20%3D%20I_%7Bmin%7D%20V%5C%5C3.784%20%3D%205I_%7Bmin%7D%5C%5CI_%7Bmin%7D%20%3D%20%5Cfrac%7B3.784%7D%7B5%7D%20%5C%5CI_%7Bmin%7D%20%3D%200.7568%20A)
If the cooler is supposed to work for 4 hours, t = 4 hours
![I_{min} = 0.7568 * 4\\I_{min} = 3.03 Amp-hr](https://tex.z-dn.net/?f=I_%7Bmin%7D%20%3D%200.7568%20%2A%204%5C%5CI_%7Bmin%7D%20%3D%203.03%20Amp-hr)
Minimum battery size needed = 3.03 Amp-hr
I don’t know what you mean by that
Answer:
no need for that
Explanation:
they are not the same at all
Answer:
shoe box covered in aluminum foil