Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
Answer:
The angle is 
.
Step-by-step explanation:
The building is 35 feet tall, and the rope is 400 feet long.Applying the trigonometric function, we have;
Sin θ = 
The height of the building represents the opposite side, while the length of the rope represents the hypotenuse. Thus;
Sin θ = 
Sin θ = 0.0875
θ = 
0.0875
= 
The angle made by the rope with respect to the ground is approximately .
X+x²=30
x²+x-30=0
(x+6)(x-5)=0
x=-6 or x=5
Answer:
5
Step-by-step explanation:
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The inequalities are matched with their correct graph respectively as follows:
- D ⇒ {(x, y): y > x²}.
- G ⇒ {(x, y): y ≥ x²+ 3
- C ⇒ {(x, y): y ≤ 3x² + 2}
- A ⇒ {(x, y): y ≥ 2x² - 5x + 1}
- J ⇒ x²- 3x ≥ 0
- H ⇒ x² - 3x + 2 ≤ 0
- B ⇒ {(x, y): y ≤ 1 - x²}
- B ⇒ {(x, y): y ≥ -1}
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.
<h3>What is an inequality?</h3>
An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments:
- Less than (<).
- Greater than (>).
- Less than or equal to (≤).
- Greater than or equal to (≥).
In Geometry, if the leading coefficient of a quadratic equation is greater than (>) zero, the parabolic curve would open upward while the parabolic curve would open downward when the leading coefficient of a quadratic equation is less than (<) zero.
Read more on graph of inequalities here: brainly.com/question/24372553
#SPJ1
Complete Question:
Match the questions with the graphs that are labeled A-H. (keep in mind that some questions might have the same answer)
1. A = {(x, y): y > x^2}
2. B = {(x, y): y ≥ x^2+ 3}
3. C = {(x, y): y ≤ 3x^2 + 2}
4. D = {(x, y): y ≥ 2x^2- 5x + 1}
6. x^2- 3x ≥ 0
7. x^2- 3x + 2 ≤ 0
8. {(x, y): y ≤ 1 - x^2}
9. {(x, y): y ≥ -1}
