Pythagoras theorem ! (a²+b²=c²)
Q1) AC = √4.8²+3.6²
= √36
= 6cm
Q2) AB= √17.55² - 6.75²
= √262.44
= 16.2cm
Q3) BC= √14² - 6²
= √160
= 12.64911
= 12.6 cm (to 3sf)
(x+6)(x+6) is the equation to find the area of the second square
Answer:
½
Step-by-step explanation:
the scale factor of dilation = 6/12 = ½
Answer:
The distance added to each dimension is 2 yards.
Step-by-step explanation:
The initial dimensions of the rectangular fence is 8 yards by 4 yards.
The initial area of the rectangular fence = area of a rectangle
area of a rectangle = length x width
So that,
The initial area of the fence = 8 x 4
= 32
The initial area of the fence is 32 square yards.
But, with the new dimensions, area = 60 square yards.
(4 + x) x (8 + x) = 60
+ 12x + 28 = 60
+ 12x - 32 = 0
(x + 14) = 0 or (x - 2) = 0
x = -14 or x =2
Thus, x = 2
The distance added to each dimension is 2 yards.
Answer:
It should be D because I have done that a couple days ago