Let's call the team members: y(ou), k, ma, mi, d, s , that's 6 members.
We know that the number of candies is 18+23+20+28 (which is 89) plus whatever Simon and Doug found.
If the average per person is 22, then all people in total found 6*22=132.
We don't know how much doug and Simon found, but together they found 132-89=32+11=43,
Once we know how much Doug found, we can subtract it from 43 and we'll know.
From all the people so far, Michelle found the most, but it could be that either Doug or Simon found more: the problem is we don't have enough information now to find out.
TRUE. I don't know for other languages, but in English you surely can do that.
Answer:
see explanation
Step-by-step explanation:
the sum to n terms of an arithmetic sequence is
=
[2a + (n - 1)d ]
where d is the common difference and a is the first term
here d = 9 - 7 = 7 - 5 = 2 and a = 5, hence
=
[(2 × 5) + 2(n - 1) ]
=
(10 + 2n - 2)
=
(2n + 8)
= n² + 4n
When sum = 165, then
n² + 4n = 165 ← rearrange into standard form
n² + 4n - 165 = 0 ← in standard form
(n + 15)(n - 11) = 0 ← in factored form
equate each factor to zero and solve for n
n + 15 = 0 ⇒ n = - 15
n - 11 = 0 ⇒ n = 11
but n > 0 ⇒ n = 11
Answer:
A
Step-by-step explanation:
these two triangles are similar
therefore corresping sides are proportionate
12/8=9/x
12x=72
x=72/12=6