QUESTION 3
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles of the kite are congruent.

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QUESTION 4
RH is the hypotenuse of the right triangle formed by the triangle with side lengths, RH,12, and 20.
Using the Pythagoras Theorem, we obtain;





QUESTION 5
The given figure is an isosceles trapezium.
The base angles of an isosceles trapezium are equal.
Therefore
QUESTION 6
The measure of angle Y and Z are supplementary angles.
The two angles form a pair of co-interior angles of the trapezium.
This implies that;



QUESTION 7
The sum of the interior angles of a kite is
.
.
.
.
.
But the two remaining opposite angles are congruent.

.
.
.
.
QUESTION 8
The diagonals of the kite meet at right angles.
The length of BC can also be found using Pythagoras Theorem;




QUESTION 9.
The sum of the interior angles of a trapezium is
.
.
.
But the measure of angle M and K are congruent.
.
.
.
.
-5/2 is equivalent to -2.5, and if you multiply 2.5 by 2 you get 5, and you have to have the negative, so add that to the 5 and you get -5. Hope this helps!
Answer:
<em>A</em>(-3, 6), <em>B</em>(-1, -2), <em>C</em>(-7, 1)
Step-by-step explanation:
To the pre-image after a 270°-counterclockwise rotation [90°-clockwise rotation], just reverse it by doing a 270°-clockwise rotation [90°-counterclockwise rotation]:
Extended Rotation Rules
- 270°-clockwise rotation [90°-counterclockwise rotation] >> (x, y) → (-y, x)
- 270°-counterclockwise rotation [90°-clockwise rotation] >> (x, y) → (y, -x)
- 180°-rotation >> (x, y) → (-x, -y)
So, perform your rotation:
270°-clockwise rotation [90°-counterclockwise rotation] → <em>C</em><em>'</em>[1, 7] was originally at <em>C</em>[-7, 1]
→ <em>B'</em>[-2, 1] was originally at <em>B</em>[-1, -2]
→ <em>A</em><em>'</em>[6, 3] was originally at <em>A</em>[-3, 6]
I am joyous to assist you anytime.
Three miles a day should be the correct answer