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e-lub [12.9K]
3 years ago
13

A sample of argon has a volume of 1.2 L at STP. If the temperature is

Chemistry
1 answer:
kherson [118]3 years ago
7 0

Answer:

the new volume would be 1.62 L

Explanation:

stp is 0 degrees C or 273.15 K and 1atm for the pressure

22 degrees C is 295.15 K

use the combined gas law formula and solve for v2

v2=p1(v1)(t2)/p2(t1)

v2=1atm(1.2L)(295.15)/0.8atm(273.15K)

v2=1.62

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lead can react with oxygen gas. If lead (IV) oxide is the product of the reaction, how would the reaction be classified
slamgirl [31]

Answer:

this reaction is an oxidation reaction

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ollegr [7]

Answer:

Difference in the potential energy of the reactants and products

Explanation:

 

The products have a lower potential energy than the reactants, and the sign of ΔH is negative. In an endothermic reaction, energy is absorbed. The products have a higher potential energy than the reactants, and the sign of ΔH is positive.

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2 years ago
Read “The Ozone Hole” and answer the question below. Write a short evaluation of the article’s reliability and scientific worth.
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6 0
3 years ago
Read 2 more answers
How many grams of O₂ are required to react completely with 14.6 g of Na to form sodium oxide, Na₂O?
Bad White [126]

The balanced chemical reaction is :

O_2 + 4Na \ -> \ 2Na_2O

Number of moles of Na, n = \dfrac{14.6}{23} = 0.635 \  mol .

Now, from balance chemical reaction we can see that 1 mole of oxygen reacts with 4 moles of sodium.

So, number of moles of oxygen are :

n = \dfrac{0.635}{4}\  mole

So, amount of oxygen required is :

m = \dfrac{0.635 \times 32}{4}\  gm\\\\m = 5.08 \ gm

Therefore, 5.08 gram of oxygen will react with 14.6 gram of sodium.

7 0
2 years ago
What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

6 0
2 years ago
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