A sample of argon has a volume of 1.2 L at STP. If the temperature is
1 answer:
Answer:
the new volume would be 1.62 L
Explanation:
stp is 0 degrees C or 273.15 K and 1atm for the pressure
22 degrees C is 295.15 K
use the combined gas law formula and solve for v2
v2=p1(v1)(t2)/p2(t1)
v2=1atm(1.2L)(295.15)/0.8atm(273.15K)
v2=1.62
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