1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
e-lub [12.9K]
3 years ago
13

A sample of argon has a volume of 1.2 L at STP. If the temperature is

Chemistry
1 answer:
kherson [118]3 years ago
7 0

Answer:

the new volume would be 1.62 L

Explanation:

stp is 0 degrees C or 273.15 K and 1atm for the pressure

22 degrees C is 295.15 K

use the combined gas law formula and solve for v2

v2=p1(v1)(t2)/p2(t1)

v2=1atm(1.2L)(295.15)/0.8atm(273.15K)

v2=1.62

You might be interested in
A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?
Ivan

Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

  • To solve this problem, we can use the mathematical relation:

ν = \sqrt{3RT/M}

Where, ν is the speed of light in a gas <em>(ν = 449 m/s)</em>,

R is the universal gas constant <em>(R = 8.314 J/mol.K)</em>,

T is the temperature of the gas in Kelvin <em>(T = 20 °C + 273 = 293 K)</em>,

M is the molar mass of the gas in <em>(Kg/mol)</em>.

ν = \sqrt{3RT/M}

(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,

<em>by squaring the two sides:</em>

(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,

∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.

<em>∴ The molar mass of the gas is 36.25 g/mol.</em>


7 0
3 years ago
The equilibrium constant for the reaction
FinnZ [79.3K]

Answer: The concentrations of Cl_2 at equilibrium is 0.023 M

Explanation:

Moles of  Cl_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol

Volume of solution = 1 L

Initial concentration of Cl_2 = \frac{0.14mol}{1L}=0.14M

The given balanced equilibrium reaction is,

                            COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial conc.           0.14 M           0 M       0M    

At eqm. conc.     (0.14-x) M        (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}

Now put all the given values in this expression, we get :

4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of Cl_2 at equilibrium is 0.023 M

7 0
3 years ago
T = 409.5 K, P = 1.50 atm: V = ?L
Molodets [167]

Explanation:

T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.

7 0
2 years ago
I’m very confused on how to solve this
Bond [772]
Recall that density is Mass/Volume. We are given the mL of liquid which is volume so all we need is mass now. We are given the mass of the granulated cylinder both with and without the liquid, so if we subtract them, we can get the mass of the liquid by itself. So, 136.08-105.56= 30.52g. This is the mass of the liquid. We now have all we need to find the density. So, let’s plug these into the density formula. 30.52g/45.4mL= 0.672 g/mL. This is our final answer since the problem requests the answer in g/mL, but be careful, because some problems in the future may ask for g/L requiring unit conversions. Also note that 30.52 was 4 sigfigs and 45.4 was 3 sigfigs, and so dividing them required an answer that was 3 sigfigs as well, hence why the answer is in the thousandths place
4 0
3 years ago
What was the key design change for hfc-134a a/c systems versus CFC 12 a/c systems
BabaBlast [244]
Answer is: key design change for HFC-134a A/C systems versus CFC-12 A/C systems was quick couple service fitting and that design reduce venting and mixing of refrigerants during service.

<span> Level of contamination is also reduced and the emission of refrigerants and greenhouse gases (sulfur dioxide, carbon dioxide) is also reduced.</span>

6 0
3 years ago
Other questions:
  • Explain why we did not see distinct lines (like on an emission spectrum) when the metal salts were burned.
    12·1 answer
  • Consider the following balanced equation:
    9·1 answer
  • Red paint mixed with blue paint becomes purple. What is the most likely cause of this color change?
    14·1 answer
  • Describe the relationship between intrapulmonary pressure, atmospheric pressure, and air flow during normal inspiration and expi
    7·1 answer
  • Chemical reactions in which large molecules are built from small molecules are classified as ______ reactions. In contrast, ____
    8·1 answer
  • A solution containing a mixture of 0.0333 M0.0333 M potassium chromate ( K2CrO4K2CrO4 ) and 0.0532 M0.0532 M sodium oxalate ( Na
    15·1 answer
  • 4. I get it! Now I know that Earth moves by –
    5·1 answer
  • How would you make 5mls of a solution that is 2.0% lactose and 0.1M SPG buffer from separate stock solutions that are 6% lactose
    14·1 answer
  • Please answer quick!!!
    6·1 answer
  • 5. A 5.00 g sample of an unknown substance was heated from 25.2 C to 55.1 degrees * C , and it required 133 to do so. Identify t
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!