The group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from <u>Alkenes</u>
<h3>What are organic compounds?</h3>
Organic compounds are compounds which contains carbon and hydrogen
Some few classes or organic compounds or hydrocarbons are as follows:
- Alkanes
- Alkenes
- Alkynes
- Alkanols
- Alkanoic acid
- Ketones
- Esters
So therefore, the group of unsaturated hydrocarbons which 2 carbons are double bonded together, with H bonded to the left, and C H 2 bonded below left, above right, and below right is derived from <u>Alkenes</u>
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Ionic compounds are formed by the complete transfer of electrons from more electronegative elements to less electronegative elements.
7. <u>Sodium Nitride (Na₃N)</u> is an ionic substance.
8. The ionic formula for <u>Lithium Oxide is Li₂O</u>
9. The <u>compound SrF₂</u>
10. Aluminum Sulfide is a chemical compound with the <u>formula Al₂S₃.</u>
An ionic compound is a chemical compound composed of ions held together via electrostatic forces termed ionic bonding. The compound is neutral standard but includes definitely charged ions known as cations and negatively charged ions known as anions.
An ionic compound is a chemical compound composed of ions held collectively by means of electrostatic forces termed ionic bonding. The compound is neutral normal however consists of positively charged ions known as cations and negatively charged ions referred to as anions. Ionic compounds incorporate ions and are held collectively via the attractive forces of most of the oppositely charged ions.
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Answer:
Hello, there!
In order to solve problems like this DO PEMDAS
The Exponent:
So, equals 4
Your problem becomes
Now we have to do what is in the (
( the is a )
And
Problem becomes
So, this means that your answer would be
Good luck on your assignment and enjoy your day!
kjExplanation:
Answer: A volume of 500 mL water is required to prepare 0.1 M 
from 100 ml of 0.5 M solution.
Explanation:
Given: 
= 0.1 M, 
= ?
= 0.5 M, 
= 100 mL
Formula used to calculate the volume of water is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M from 100 ml of 0.5 M solution.
