Answer:
He multiplied the divisor by 100 and the dividend by 10.
Step-by-step explanation:
Given that
Divisor = 0.52
And, the dividend is 754
It can be written as
Divisor is 52 i.e. (0.52 × 100)
And, the dividend is 7540 i.e. (754 × 10)
Now if we multiplied by 100 and divide by 10 so it gives the same result
Therefore the last option is correct and the same is to be considered
And all the other options are wrong
Answer:
Substitution method can be used
Step-by-step explanation:
Given the system of equations
y = 2x-1 ....1
-12x + 3y = 9 ....2
The best method to use id the substitution method
Substitute equation 1 into 2;
From 2;
-12x + 3y = 9
-4x + y = 3
-4x + 2x-1 = 3
-2x -1 = 3
-2x = 3+1
-2X = 4
x = -4/2
x = -2
Substitute x = -2 into 1
y = 2x - 1
y = 2(-2)-1
y = -4-1
y = -5
Hence the solution to the system of equation is (-2, -5)
Yes. For right triangles, the sum of the squares of the shorter sides is equal to the square of the longer side. Thus, this is a right triangle if 10^2+24^2=26^2. Expanding these squares, we have 100+576=676, which is true. Thus, the triangle is right.
The answer you are looking for is x=-2.
Solution/Explanation:
Writing out the equation
3[-x+(2x+1)]=x-1
Simplifying inside of the brackets first
Combining like terms, since -x+2x=x
3(x+1)=x-1
*You can remove the parenthesis, if preferred.
Using the Distributive Property on the left side of the equation
3x+3=x-1
Now, subtracting the "x" variable from both sides
3x+3-x=x-x-1
"x-x" cancels out to 0.
3x+3-x=-1
Combining like terms and simplifying
3x-x+3=-1
2x+3=-1
Subtracting 3 from both sides of the equation
2x+3-3=-1-3
"3-3" cancels out to zero.
2x+0=-1-3
2x=-1-3
Simplifying the right side of the equation
2x=-4
Finally, dividing both sides by 2
2x/2=-4/2
Simplifying the final part of the problem
Since 2x/2=x and -4/2=-2
x=-2
So, therefore, the final answer is x=-2.
Hope that this has helped you. Good day to you.
Answer:
Perimeter of the quadrilateral PQRS is 25 units
Step-by-step explanation:
From the figure attached,
PQ is a tangent to the given circle so m∠PQR = 90°
Now we apply Pythagoras theorem in the ΔPQR,
PR² = PQ² + QR²
(PT + TR)²= PQ² + 5²
(4 + 5)² = PQ² + 25
81 = PQ² + 25
PQ = √(81 - 25)
= √56
≈ 7.5 units
PQ ≅ PS ≅ 7.5 units
[Since measures of tangents drawn from a point to a circle are always equal]
Perimeter of PQRS = PQ + QR + RS + PS
= 7.5 + 5 + 5 + 7.5
= 25 units
Therefore, perimeter of the quadrilateral PQRS is 25 units.
