Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
-1.5
Step-by-step explanation:
4x² + 4x - 3 = 0
(2x + 3)(2x - 1) = 0
2x + 3 = 0 or 2x - 1 = 0
x = -3/2 or x = 1/2
Answer: -1.5
7.C I think is the answer
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Step-by-step explanation:
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