Answer:
D
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 3x - 4 ← is in slope- intercept form
with slope m = 3
Parallel lines have equal slopes , so
y = 3x + c ← is the partial equation
To find c substitute (2, 1) into the partial equation
1 = 6 + c ⇒ c = 1 - 6 = - 5
y = 3x - 5 ← equation of parallel line → D
Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Answer:
=5w3+8w2−10w+2
Step-by-step explanation:
Simplify
1
Distribute
2
(
2
+
3
−
5
)
+
3
3
+
2
(
2
+
1
)
2
3
+
6
2
−
1
0
+
3
3
+
2
(
2
+
1
)
2
Distribute
2
3
+
6
2
−
1
0
+
3
3
+
2
(
2
+
1
)
2
3
+
6
2
−
1
0
+
3
3
+
2
2
+
2
3
Combine like terms
2
3
+
6
2
−
1
0
+
3
3
+
2
2
+
2
5
3
+
6
2
−
1
0
+
2
2
+
2
4
Combine like terms
5
3
+
6
2
−
1
0
+
2
2
+
2
5
3
+
8
2
−
1
0
+
2
sorry if it don't make sense ;c
