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Simora [160]
3 years ago
13

What points are coplanar??

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
6 0

Coplanar means that points lie in the same plane. Since A, E, and D all lie on the back wall, they are coplanar.

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A train has 6 passenger cars and each car has 4 columns of seats and each column holds 50 passengers. If one of the cars has 25
Tema [17]
Given:
The train has 6 passenger cars
Each car has 4 columns
And 1 column hold 50 passengers

So, total of seats will be = 6 * 4 * 50 = 1200

Now, there are 25 empty seats, 

therefore the correct equation will be : 

Number of seats per car: 4 × 50 = 200

Total number of seats: 200 × 6 = 1,200

Number of passengers: 1,200 − 25 = p




6 0
3 years ago
The midpoint of AB is M(0, 3) If the coordinates of A are (4, - 1) , what are the coordinates of B?
Harlamova29_29 [7]

-4;4

XB=0*2-4

YB=3*2-(-1)

3 0
2 years ago
Which property can be used to expand the expression -2(3/4x+7)
geniusboy [140]

Answer:

B. <u>the distributive property</u>

Step-by-step explanation:

<u>Distributive </u><u>property</u> can be used to expand the expression -2(3/4x+7).

When that property is used, we need to distrubute the monomial to the binomial which is the two terms.

- 2( \frac{3}{4} x  + 7) \\  \Longrightarrow \boxed{- 2( \frac{3}{4} x) +  - 2(7)}

#BrainliestBunch

4 0
3 years ago
Which word is used to name the bold number?
prohojiy [21]
If 3 is the bold number then the answer is D. <span>#TeamAlvaxic</span>
7 0
3 years ago
Hi :) how to do question 7 ?
Gre4nikov [31]

Answer:

Step-by-step explanation:

We khow that the equation of a circle is written this way :

(x-a)²+(y-b)²=r² where (x,y) are the coordinates of the cercle's points and (a,b) the coordinates of the cercle's center and r the radius .

Our task is to khow the values of a and b :

  • We khow that the center is lying on the line 3x+2y=16⇒ 2y=-3x+16⇒ y= \frac{-3}{2}x+8  
  • We khow that the points P and Q are two points in the cercle
  • Let Ω be the center of this cercle
  • we can notice that : PΩ AND QΩ are both equal to the radius ⇒ PΩ=QΩ= r
  • So let's write the expression of this distance using vectors KHOWING THAT Ω(a,b)
  • Vector PΩ(a-4,b-6) and Vector QΩ(a-8,b-2)
  • PΩ=\sqrt{(a-4)^{2}+(b-6)^{2}  } and QΩ=\sqrt{(a-8)^{2}+(b-2)^{2}   }
  • Let's substitute a by x and b by y
  • PΩ=QΩ we substitute each distance by its expression
  • After simplyfying the expressions we get finally : -12+8x-8y=0
  • now we have -12x +8x-8y=0 and the line equation 3x+2y-16=0
  • these are simultanious equations so after solving them we get x=3.8 wich is approximatively 4 and y=2
  • we substitute a by 4 and y by 2 in PΩ to get the radius
  • we get r = \sqrt{(4-4)^{2}+(2-6)^{2}  } = 4
  • so r²= 16
  • then the equation is : (x-4)²+(y-2)²=16
5 0
3 years ago
Read 2 more answers
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