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4 years ago

A rectangular prism has its length as 6cm, breath 5cm and height 9cm. find the volume

Mathematics

1 answer:

Harrizon [31]4 years ago

3 0

Answer:

270

Step-by-step explanation:

Volume of rectangular prism = length x width x height

6 x 9 x 5= 270

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What is the solution to this equation and explain your reasoning. 4(x+7)=38

krek1111 [17]

2.5 should be correct unless im doing the problem wrong

3 0

3 years ago

Vat is 2+5+5+5-2

vodka [1.7K]

Answer:

Your answer is 15

Step-by-step explanation:

2+5= 7

7+5= 12

12+5=17

17-2= 15

6 0

3 years ago

Point A(1,9) and point B(−4,−3) are located within the coordinate plane.

AlekseyPX

Answer:

The answer to your question is 13 units

Step-by-step explanation:

Data

A (1, 9)

B (-4, -3)

distance = ?

Formula

distance = $\sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}$

Substitution

distance = $\sqrt{(-4 - 1)^{2} + (-3 - 9)^{2}}$

Simplification

distance = $\sqrt{(-5)^{2} + (-12)^{2}}$

distance = $\sqrt{25 + 144}$

distance = $\sqrt{169}$

Result

distance = 13

8 0

3 years ago

Read 2 more answers

Exercise 5.2. Suppose that X has moment generating function

soldi70 [24.7K]

Answer:

a) Mean, E(X) = - 0.5

Variance = = 9.25

b) $M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Step-by-step explanation:

Given:

moment generating function of X as:

MX(t) = $\frac{1}{2} + \frac{1}{3}e^{-4t} + \frac{1}{6} e^{5t}$

a) Now

Mean, E(X) = $M_{X}'(t=0)$

Thus,

$M_{X}'(t)=\frac{1}{3}(-4)e^{-4t}+\frac{1}{6}(5)e^{5t}$

$M_{X}'(t)=\frac{-4}{3}e^{-4t}+\frac{5}{6}e^{5t}$

also,

$E(X^{2})=M_{X}''(t=0)$

Thus,

$M_{X}''(t)=\frac{-4}{3}(-4)e^{-4t}+\frac{5}{6}(5)e^{5t}$

$M_{X}''(t)=\frac{16}{3}e^{-4t}+\frac{25}{6}e^{5t}$

Therefore,

Mean, E(X) = $M_{X}'(t=0)=\frac{-4}{3}e^{-4(0)}+\frac{5}{6}e^{5(0)}$

Mean, E(X) = - 0.5

and

$E(X^{2})=M_{X}''(t=0)=\frac{16}{3}e^{-4(0)}+\frac{25}{6}e^{5(0)}$

$E(X^{2})$ = 9.5

also,

Variance(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

b) Now,

Let f(x) be the PMF of X

Thus,

$M_{X}(t)=E(e^{tX})$

⇒ $=\sum e^{tx}p(x)$

⇒ $=\frac{1}{2}+\frac{1}{3}e^{-4t}+\frac{1}{6}e^{5t}$

Therefore,

at x = 0, P(x) = $\frac{1}{2}$

at x= - 4 ,P(x) = $\frac{1}{3}$

at x = 5, P(x) = $\frac{1}{6}$

Thus,

E(X) = $\sum xP(x)=0(\frac{1}{2})+(-4)(\frac{1}{3})+5(\frac{1}{6})$

E(X) = - 0.5

also, $E(X^{2})=\sum x^{2}P(x)=0^{2}(\frac{1}{2})+(-4)^{2}(\frac{1}{3})+5^{2}(\frac{1}{6})$

$E(X^{2})$ = 9.5

Hence,

Var(X) = E(X²) - E(X)²

⇒ 9.5 - (-0.5)²

= 9.25

4 0

4 years ago

Choose the correct way to read 32.507 in word form

Elden [556K]

32.507 in word form: Thirty-two and five hundred seven thousandths

8 0

3 years ago

A rectangular prism has its length as 6cm, breath 5cm and height 9cm. find the volume​

A rectangular prism has its length as 6cm, breath 5cm and height 9cm. find the volume