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vovikov84 [41]
3 years ago
7

LAST ONE !!! Ok here

Mathematics
1 answer:
spin [16.1K]3 years ago
7 0

Answer:

Market economy

Step-by-step explanation:

Once again this is because they are changing their prices and items for sale because of the changes in market.

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Nadine can send or receive a text message for 15 cents or get an unlimited number for 5 dollars. Write and solve an inequality t
Ne4ueva [31]
$0.15x>$5.00
x>33.3333
So if she sends or receives more than 33 text messages, she will be paying more than $5.00.
4 0
3 years ago
Solve the equation: p-5/p = 3/9
ExtremeBDS [4]

Answer;

p= (1 + sqrt. 181) / 6, (1- sqrt. 181) / 6

Hope this helps!

6 0
3 years ago
The standard deviation of a sample taken from population A is 17.6 for a sample of 25.
lawyer [7]

Answer:

The standard deviation of the sample mean differences is _5.23_

Step-by-step explanation:

We have a sample of a population A and a sample of a population B.

For the sample of population A, the standard deviation \sigma_A is

\sigma_A = 17.6

The sample size n_A is:

n_A = 25.

For the sample of population B, the standard deviation \sigma_B is

\sigma_B = 21.2

The sample size n_B is:

n_B = 30.

Then the standard deviation for the difference of means has the following form:

\sigma=\sqrt{\frac{\sigma_A^2}{n_A}+\frac{\sigma_B^2}{n_B}}

Finally

\sigma=\sqrt{\frac{17.6^2}{25}+\frac{21.2^2}{30}}\\\\\sigma= 5.23

7 0
3 years ago
Question 3
Crank

Step-by-step explanation:

Given that,

The mass of a patient = 70 kg

A 70kg patient has approximately 8 pints of blood.

The patient donates 470mL of blood.

We know that,

1 pint = 568 mL

8 pints = 4544 mL

Required fraction,

\dfrac{470}{4544}=0.1\\\\=\dfrac{1}{10}

So, the required fraction is approximately \dfrac{1}{10}.

4 0
2 years ago
A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0
3 years ago
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