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3 years ago

Someone help with this !!!

Mathematics

1 answer:

murzikaleks [220]3 years ago

4 0

The correct answer is the third choice : 25/9

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What value of w is a solution to this equation?<br> w/2 = 6<br> w = 10 or w = 12

Monica [59]

W=12 would be the correct answer. I got this because if you divided 12 by 2, (12/2) you would get 6!

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3 years ago

Read 2 more answers

Which of the following is true about the relation shown below?

Anestetic [448]

Answer:

Last on is the answer!! (The relation is a function, and the range is (-2,-1, 1, 3, 4). Hope this helps:)

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2 years ago

Whats the answer to these questions, please do not delete

lukranit [14]

Answer:

Answer is in the attached image.

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2 years ago

A ball is thrown into the air and its position is given by h ( t ) = − 6.3 t 2 + 53 t + 24 where h is the height of the ball in

nordsb [41]

Answer:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

Step-by-step explanation:

For this case we have the following function:

$h(t) = -6.3t^2 +53 t+24$

In order to maximize this function we need to take the first derivate respect the time and we have:

$h'(t) = -12.6 t +53$

Now we can set up the derivate equal to 0 and we have:

$-12.6 t +53 = 0$

And solving for t we got:

$t = \frac{53}{12.6}= 4.206$

For the second derivate respect the time we got:

$h''(t) = -12.6$

So then we can conclude that t = 4.206 is a maximum for the function.

And the corresponding height would be:

$h(t=4.206) = -6.3(4.206)^2 +53*4.206+24= 135.468 ft$

So the maximum occurs at t = 4.206 s and with a height of 135.468 m

8 0

3 years ago

(y-x)(y+x) equals to<br>

Len [333]

It equals y^2+yx-yx-x^2

6 0

3 years ago