The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:
x+y=18 (because the problem tells you there were 18 cars in total)
3000x+5000y=60000 (because that is the total weight in the problem)
Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.
x=18-y
Then you have to plug that into the other equation to get:
3000(18-y)+5000y=60000
Simplify and solve for y:
54000-3000y+5000y=60000
54000+2000y=60000
2000y=6000
y=3
Now that you know what y equals, you can put it into the equation we solved for x:
x=18-3
x=15
So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.
Answer:
y=2
x=3
Step-by-step explanation:
make x - y = 1 into x= y + 1
put that wherever x is in the other equation
so y + 1 + 2y =7. then combine like terms into 3y =6. then divide 6 by 3 so you get y = 2
then substitute 2 into the y in the equation x - y = 1 and you get x = 3
The solution to the problem is as follows:
a cube has sides s
V = s^3 ---> differentiating
dV/dt = 3s^2 * ds/dt
0.5 ft^3 / min = 3 * (12ft)^2 * ds/dt
(1/2) ft^3 / min = 3 * 144 ft^2 * ds/dt
(144/6) ft^3 / ( ft^2 min ) = ds/dt
<span>24 ft / min = ds/dt
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Check the picture below
notice, the "a" side goes from -2 to 11
and the "b" side goes from 2 down to -4
