Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.
You can subtract 60 in order to put this in standard form
48x^2+44x-60 = 0
From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.
(-b+-sqrt(b^2-4ac))/2a
(-44+-sqrt(44^2-4(48)(-60)))/2(48)
Then solve.
There is probably a better way, but this should give you the two roots/solutions.
Tan^2x + 1 + tanx - 3 = 0 tan^2x + tanx - 2 = 0 (tanx + 2)(tanx - 1) = 0 tanx = -2 or tanx = 1 x = 2.034 radians or x = 5.176 radians or x = pi/4 radians or x = 5pi/4 radians
