I'm not good with any math that is above per algebra sorry.
Answer:-6
Step-by-step explanation:
to solve for slope, you have to do (y1-y2)/(x1-x2)
in this problem, that turns into (-1-(-13))/(-2-0)
which is (-1+13)/(-2-0) which is 12/-2 which is -6, your answer
Answer:
Midpoint of side EF would be (-.5,4.5)
Step-by-step explanation:
We know that the coordinates of a mid-point C(e,f) of a line segment AB with vertices A(a,b) and B(c,d) is given by:
e=a+c/2,f=b+d/2
Here we have to find the mid-point of side EF.
E(-2,3) i.e. (a,b)=(2,3)
and F(1,6) i.e. (c,d)=(1,6)
Hence, the coordinate of midpoint of EF is:
e=-2+1/2, f=3+6/2
e=-1/2, f=9/2
e=.5, f=4.5
SO, the mid-point would be (-0.5,4.5)
Ok this one is easier than you might think. The line equals 180 degrees since it is a straight line, therefore you need to do 180-27 to get what y equals. Y=153
Move everything to one side
Equation
2x^2 - 5x -3 = 0
Sq rt means square root or radical sign
Quadratic equation-> x = - (b) +/- Sq rt b^2 -4ac
2a
- (-5) +/- Sq rt (-5)^2 - 4(2)(-3)
2 (2)
5 +/- Sq rt 25 + 24
4
Sq rt 29 = 5.38
5 + Sq rt 29 divides over 4 and 5 - Sq rt 29 divides over 4.