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steposvetlana [31]
3 years ago
9

#include

Computers and Technology
1 answer:
gavmur [86]3 years ago
4 0

Answer:

See explaination

Explanation:

#include <fstream>

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

// Fill in the code to define payfile as an input file

ifstream payfile;

float gross;

float net;

float hours;

float payRate;

float stateTax;

float fedTax;

cout << fixed << setprecision(2) << showpoint;

// Fill in the code to open payfile and attach it to the physical file

// named payroll.dat

payfile.open("payroll.dat");

// Fill in code to write a conditional statement to check if payfile

// does not exist.

if(!payfile)

{

cout << "Error opening file. \n";

cout << "It may not exist where indicated" << endl;

return 1;

}

ofstream outfile("pay.out");

cout << "Payrate Hours Gross Pay Net Pay"

<< endl << endl;

outfile << "Payrate Hours Gross Pay Net Pay"

<< endl << endl;

// Fill in code to prime the read for the payfile file.

payfile >> hours;

// Fill in code to write a loop condition to run while payfile has more

// data to process.

while(!payfile.eof())

{

payfile >> payRate >> stateTax >> fedTax;

gross = payRate * hours;

net = gross - (gross * stateTax) - (gross * fedTax);

cout << payRate << setw(15) << hours << setw(12) << gross

<< setw(12) << net << endl;

outfile << payRate << setw(15) << hours << setw(12) << gross

<< setw(12) << net << endl;

payfile >> hours ;// Fill in the code to finish this with the appropriate

// variable to be input

}

payfile.close();

outfile.close();

return 0;

}

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Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
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In a switch statement, if a break statement is missing, _______________. Select one: a. the default case is automatically execut
Aleks [24]

Answer:

c. execution falls through the next branch until a break statement is reached

Explanation:

In a switch statement, if break is missing, then program continues to the next cases until it finds a break statement.

Consider the following example!

Example:

#include <iostream>

using namespace std;

int main()

{

  int choice = 1;

  switch (choice)

  {

      case 1:

      printf("This is case 1, No break\n");

      case 2:

      printf("This is case 2, No break\n");

      case 3:

      printf("This is case 3, with break\n");

      break;

      default: printf("Error! wrong choice\n");

  }

  return 0;

}

Output:

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This is case 2, No break

This is case 3, with break

We have 3 cases here and case 1 and 2 don't have break statements, only case 3 has a break statement.

We called the case 1, then program continued to case 2,  and finally to case 3 where it finds the break statement and terminates.

Therefore, we conclude that in a switch statement, if a break statement is missing, then execution falls through the next branch until a break statement is found.

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arrives at work on time or early

waits for supervisor to give directions

works quickly and accurately

shows initiative

communicates effectively

sets clear goals to achieve success

Explanation:

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In the event that you answer that it is not classified, it also gives rise to the reason that the information is not of simple access also exposing you to answering more questions and having to release the confidential information.

By denying both confidentiality and non-confidentiality, you refer to ignorance of the subject by avoiding further questions about such information on the web.

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