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marin [14]
2 years ago
15

Tony’s club is selling oranges to raise money. For every box they sell, they get 1 1/8 dollars profit. They have sold 75 boxes a

lready. How many more boxes must they sell to raise 180 dollars?
Mathematics
1 answer:
dmitriy555 [2]2 years ago
8 0

Tony’s club is selling oranges to raise money. For every box they sell, they get 1 1/8 dollars profit. They have sold 75 boxes already. How many more boxes must they sell to raise 180 dollars?

Answer: We are given:

The amount of money Tony's club get for every box they sell =1 \frac{1}{8} =1.125 dollar

They amount of money Tony's club has raised by selling 75 boxes is:

75 \times 1.125=84.375 dollars

The amount of money Tony's club is required to raise = 180 dollars

The remaining need to be raised is :

180-84.375=95.625 dollars

Therefore, the number of more boxes to be sold are:

\frac{95.625}{1.125}=85

Hence, 85 more boxes they must sell to raise 180 dollars

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Stella [2.4K]

The values are x=8 and y=10

Explanation:

From the figure, we can see that the two quadrilaterals are similar.

Thus, by the property of quadrilateral, for similar quadrilaterals, their corresponding angles and sides are congruent. Thus, we have,

∠D = ∠S, ∠E = ∠P, ∠G = ∠R and ∠F = ∠Q

Also, GF = QR and DE = PS

Where QR = 2x-4 and ∠D = 102°, ∠G = 84° and ∠F = 68°, ∠Q = (6y+x)°

Hence, to determine the value of x for the side QR, we have,

Equating the values in GF = QR,we get,

12=2x-4\\16=2x\\8=x

Thus, the value of x is 8.

Substituting x in the angle Q to determine the value of y.

Thus, we have,

∠F = ∠Q

68=6y+x\\68=6y+8\\60=6y\\10=y

Thus, the value of y is 10.

Hence, The values are x=8 and y=10

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3 years ago
I don’t know the answer
anastassius [24]
I THINK IT IS B

B) D(X)= X-8x4 
7 0
3 years ago
1. What are the roots of 4x2 = 8x - 7?
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6 0
3 years ago
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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