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rodikova [14]
3 years ago
11

Scientists have found that the life span of a mammal living in captivity is related to the mammals mass. The life span in years

L can be approximated by the formula L=12m^1/5, where m is the mammal's mass in kilograms. How much longer is the life span of a lion compared with that of a wolf?
wolf=32 kg
lion=243 kg
Mathematics
1 answer:
Tatiana [17]3 years ago
7 0
To know the life span of the wolf and the lion, we simply substitute their mass to the formula for L.

Mass of wolf:
L=12 m^{ \frac{1}{5} }= 12 (32)^{ \frac{1}{5} }=24

Mass of lion:
L=12 m^{ \frac{1}{5} }= 12 (243)^{ \frac{1}{5} }=36

Therefore, the wolf has a life span of 24 and the lion has a life span of 36. With this information, we can determine how much longer the life span of the lion is:
36-24=12

ANSWER: The life span of the lion is 12 longer than the life span of the wolf.
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Solve for x <br>3(x - 2) = 6x - 12<br>​
nalin [4]

Answer:

The answer is 2

Step-by-step explanation:

Here's how I got it:

3(x - 2) = 6x - 12

Multiply 3 times x and 3 times 2, this is what you would get

3x - 6 = 6x - 12

Then, subtract the lowest x with the bigger X, this way you would have x on one side:

3x - 6 = 6x - 12

-3x        -3x

This is what you should have after this:

-6 = 3x - 12

Now, to get the variable (letter that represents a number) by itself, you have to add 12 to both sides like this:

-6 = 3x - 12

+12        +12

You would get this:

6 = 3x

Finally, you have to get x by itself, so you have to divide 3 on both sides like this

6/3 = 3/3 x

That's why, your answer is 2

5 0
3 years ago
Carpet a room 12ft by 8ft. How many yards of sq carpet
ira [324]
You need 96 Square yards of carpet
3 0
4 years ago
Simplify 8/-3 ÷ -4/9<br><br> A. -8<br> B. -6<br> C. 6<br> D. 8
geniusboy [140]

Answer:

C. 6

Step-by-step explanation:

to divide by a fraction multiply by the recirpocal of that fraction.

8/3 ÷ 9/4

reduce the numbers with GCF 4 which equals 2/3 x 9

reduce the numbers with GCF 3 which equals 2x3= 6

4 0
3 years ago
Leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. The triangular base has a
Illusion [34]

Answer: The answer is (A)~~x=\dfrac{-7+\sqrt{193}}{4}.


Step-by-step explanation: Given that Leonhard wants to place a triangular based cabinet in the corner of his room which is rectangular in shape.

The base and height of the triangular cabinet are

b=(2x+3)~\textup{feet},\\\\h=(3x+6)~\textup{feet}.

Therefore, area of the triangular cabinet is given by

a=\dfrac{1}{2}\times b\times h=\dfrac{1}{2}(2x+3)(3x+6)~\textup{sq. feet.}

Now, the length and breadth of the rectangular room are 30 feet and 20 feet respectively. Therefore, the area of the room is given by

A=30\times 20=600~\textup{sq. feet.}

According to the question,

a=6\%\times A\\\\\Rightarrow \dfrac{1}{2}(2x+3)(3x+6)=\dfrac{6}{100}\times 600\\\\\Rightarrow (2x+3)(3x+6)=24\times 3\\\\\Rightarrow (2x+3)(x+2)=24\\\\\Rightarrow 2x^2+7x-18=0\\\\\Rightarrow x=\dfrac{-7\pm\sqrt{7^2-4\times 2\times(-18)}}{2\times 2}\\\\\\\Rightarrow x=\dfrac{-7\pm\sqrt{193}}{4}.

Since the length of something cannot be negative, so the value of 'x' is

x=\dfrac{-7+\sqrt{193}}{4},

because if we take the other value of 'x', the values of (2x+3) and (3x+6) will become negative which is not possible.

Thus, (A) is the correct option.



5 0
3 years ago
Professor Anthony calculated a chi-square statistic of 16.22 with df=8. What is the critical value of chi-square in order to tes
Pavlova-9 [17]

Answer:  The P-Value is .039337. The result is not significant at p < .01.

Step-by-step explanation:

In the following Chi square table attached, the value is of df=8 and chi square statistic value of 16.22 is found to be between (15.507, X²₀.₀₅) and    ( 17.353, X²₀.₀₂₅).

Using the table for critical value calculation:-

Df=8 Critical value for 1%= 1.646, and we calculated our value of 17.353.

We can reject is on the basis of X²calculated > X²Critical.

The outcome doesn't falls to be in 1% of the distribution.

or

We can reject it on basis that the outcome between X²₀.₀₅ and X²₀.₀₂₅ whereas the required level of upper distribution is X²₀.₀₁

5 0
3 years ago
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