Can someone help me figure out how to do this?
2 answers:
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Answer:
A
Step-by-step explanation:
The velocity of a moving body is given by the equation:
Is the velocity is <em>positive </em>(v>0), then our object will be moving <em>forwards</em>.
And if the velocity is negative (v<0), then our object will be moving <em>backwards</em>.
We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:
By substitution:
Solve. To do so, we can first solve for <em>t</em> and then test values. By factoring:
Zero Product Property:
Now, by testing values for t<1, 1<t<4, and t>4, we see that:
So, the (only) interval for which <em>v</em> is <0 is the second interval: 1<t<4.
Hence, our answer is A.
Answer:
≈ 12.6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle.
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.
let x be the third side, then
x² + 6² = 14²
x² + 36 = 196 ( subtract 36 from both sides )
x² = 160 ( take the square root of both sides )
x = ≈ 12.6 ( to the nearest tenth )
Hey there!☺
Equation
−4(10 − a) = 36 Simplify both sides
(−4)(10) + (−4)(−a) = 36 Distribute
−40 + 4a = 36
4a − 40 = 36
4a - 40 + 40 = 36 + 40 Add 40 to both sides
4a = 76
4a/4 = 76/4 Divide both sides by 4
76/4 = 19 Simplify 76/4
a = 19
Hope this helps!