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3 years ago

What is the oxidation number of sulfur in na2s2o3?

Chemistry

1 answer:

nignag [31]3 years ago

8 0

Na₂S₂O₃

(+1 × 2) + (2 × x) + (-2 × 3) = 0

2+2x-6 = 0

2x-4 = 0

2x = 4

x = 4/2

x = +2....

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Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

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